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Alexeev081 [22]
3 years ago
5

¿Que tiempo se tardara en escucharse el retumbo de un volcan situado a 58km?

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

How long will it take to hear the rumbling of a volcano located 58km away?

Step-by-step explanation:

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Wendy has dance class 2 days a week James has dance class 5 times a week how many more times a week does James have dance class
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You just have to do subtraction...

5-2 = 3 more times
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Michael has a total of$4.40 in dimes (1 dime=$0.10) and quarters (1quarter=$0.25), and he has 20 coins in total. Which of the fo
Vesnalui [34]
A) d+q=20
0.1d+0.25q=4.40 Let's just read what this says: first, # of dimes (d) plus # of quarters (q) is 20.The second equation can be called the VALUE EQUATION; it says that one tenth of a dollar ($0.10) times the # of dimes is part of the total monetary value, and that one quarter of a dollar ($0.25) times the # of 'quarter' coins is the other part of this stash, and it totals $4.40. VOTE FOR A.
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3 years ago
HELP !!!!!!!!!!!!!!!!!!!!!!!
Lelu [443]

Answer:

25\pi Or 78.5 units³

Step-by-step explanation:

1/3πr²h

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7 0
3 years ago
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Dina and Masha start cycling on a 20 km bike path at the same time. When Dina reaches the end of the path, Masha still has 4 km
sammy [17]

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

Speed=\frac{distance}{time}\\10=\frac{20}{time}\\time=\frac{20}{10}\\ time=2\ hours

The time taken by Dina is 2 hours. As masha started with dina but she was 4 km of the path left to cycle,

her distance covered in 2 hours was:

Distance\ covered\ by\ Masha\ in\ 2\ hours=20-4\\=16 km

So we know the time and distance:

Now,

Speed\ of\ Masha=\frac{distance}{time}\\ =\frac{16}{2}\\ =8\ kilometer\ per\ hour

We have to calculate the time that will be needed by MAsha to complete the track:

As we know the speed and remaining distance

Speed=\frac{distance}{time}\\8=\frac{4}{time}\\ time=\frac{4}{8}\\time=0.5\ hours

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3 years ago
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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
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