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kkurt [141]
3 years ago
8

AYUDEN POR FAVOR ESTOY EN MEDIO DE UN EXAMEN!! El producto de masa de un cuerpo por su velocidad se le llama: Seleccione una: A.

Potencia B. Energía potencial C. Impulso D. Momentum
Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

La respuesta es d. Momentum

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Steven wants to keep track of how many miles he walks in a year. He expects to walk 5 miles per day, and he has
WINSTONCH [101]

Answer:

The fourth choice.

Step-by-step explanation:

Because since 90 miles is basically counted as your first day, you do the number of days, n, minus 1 and then multiply it by 5 to find the number of miles walked after the first day. Then you add it to 90.

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3 years ago
How would i graph y=2x+5
Anna35 [415]

To be able to graph this you need to start on -2 on the y-axis then move up 5 then 1 to the right

The dot should be on (1,3)

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3 years ago
PLEASE HELP DUE IN 10 MIN ITS A FINAL
Tomtit [17]

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intersecting

Step-by-step explanation:

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3 years ago
What is the solution to the following system of
Rufina [12.5K]

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i think the correct answer of these qusion is -2,3

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3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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