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Wewaii [24]
3 years ago
10

9 in

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

D.

area of triangle = 1/2 × base × height

therefore,

1/2× 9× 13= 58.5in^2

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Cual es la raiz cuadrada de 44
Dvinal [7]
Por lo que la raíz cuadrada de 44 es 2V11 (V es el signo de la raíz cuadrada) forma decimal es 6,63324958
3 0
3 years ago
I need help with my math, and only the correct answers please and if you don't mind can you teach me how to do it? It might seem
sweet-ann [11.9K]

Answer:

if you need help I'm here

Step-by-step explanation:

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7 0
3 years ago
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Simplify 8√40 - 3√90​
Colt1911 [192]

Answer:

7√10

Step-by-step explanation:

8√40 - 3√90​

8√(2^2*2*5) - 3√(3^2*2*5)

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7√10

5 0
3 years ago
How do I write 2.8 as a fraction?
ruslelena [56]
Well you see, you have 2/8, (fraction) and here is a few others,
These are COMMON. 4/16, 2/8, 6/24, etc.... 
You multiply the denominator and numerator by the same answer.
Thats how I think I learned it.
5 0
3 years ago
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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
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