Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
<h3>
Answer: 944 dollars for the week</h3>
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Explanation:
He sold $4950 worth of items. Take 12% of this amount to get
12% of 4950 = 0.12*4950 = 594
So he earns $594 in commission on top of the $350 base salary paid every week. In total, he earns 594+350 = 944 dollars for that week
This isn't the per week pay because he would need to sell exactly $4950 worth of goods each week to keep this same weekly pay.
1st option
{(3,0) e (0,9)}; {(2,0) e (0,-4)}; {(1,0) e (0,-5)}
see screenshot
sorry btw, no hablo espanol
f is given as -3
-3 is greater than -4, so use the second equation 3x-5.
replace x with -3 and calculate:
3(-3) - 5 = -9 - 5 = -14
The answer is -14.
