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3 years ago

What is the approximate solution to this equation?

2 answers:

8 0

So you could take and do each number to the third power until you get approximately 124.75.

Starting with A. it would be 4x4x4 = 64 - So it can't be A.

Now, B. it would be 5x5x5 = 125 - This would be your answer since the other numbers just get bigger and stray farther and farther away from 124. Hope this helps :)

Citrus2011 [14]3 years ago

6 0

The answer is B because 5^3 is 125 so the approximate answer is 124.75

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malfutka [58]

Answer:

So the annual percent of decay is: 7.77%

Step-by-step explanation:

If the value of a car was $18000 in 2006, and in 2016 it was worth $4000 it means, it lose 77.77% of its value in 10 years.

To calculate the percentage of decay we use the rule of three:

If the price of the car in 2006 ($18000) represents 100%, then, how much does $4000 represents?

4000*100/18000 = %22.22

Now, we know that $4000 represents 22.22% the original value, so it lose 100% - 22.22% = 77.77% of its value.

So the annual percent of decay is: 77.77% / 10 = 7.77%

7 0

4 years ago

100 points

Andru [333]

<em>Just a little note you put 50 points and not 100 </em>

The y-axis doesn't start at zero.

The intervals on the y-axis are too large.

Different bar widths are used on the same graph.

The y-axis starts at zero but has different intervals.

6 0

3 years ago

Read 2 more answers

You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if

oksian1 [2.3K]

Answer: The mean and variance of Y is $0.25 and $6.19 respectively.

Step-by-step explanation:

Given : You and a friend play a game where you each toss a balanced coin.

sample space for tossing two coins : {TT, HT, TH, HH}

Let Y denotes the winnings on a single play of the game.

You win $1; if the faces are both heads

then P(Y=1)=P(TT)= $\dfrac{1}{4}=0.25$

You win $6; if the faces are both heads

then P(Y=6)=P(HH)= $\dfrac{1}{4}=0.25$

You loose $3; if the faces do not match.

then P(Y=1)=P(TH, HT)= $\dfrac{2}{4}=0.50$

The expected value to win : E(Y)= $\sum_{i=1}^{i=3} y_ip(y_1)$

$=1\times0.25+6\times0.25+(-3)\times0.50=0.25$

Hence, the mean of Y : E(Y)= $0.25

$E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25$

Variance = $E[Y^2]-E(Y)^2$

$=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19$

Hence, variance of Y = $ 6.19

6 0

4 years ago

If f(x)=x-1/3 and g(x)=3x+1, what is (f o g)(x)?

BlackZzzverrR [31]

Answer:

$3x+\frac{2}{3}$

Step-by-step explanation:

$f(x)=x-\frac{1}{3}$

$g(x)=3x+1$

Hence, $(f o g)(x)=f(3x+1)$

But, $f(3x+1)=(3x+1)-\frac{1}{3}$

Simplifying,

$f(3x+1)=3x+(1-\frac{1}{3})$

= $f(3x+1)=3x+(\frac{3-1}{3})$

= $f(3x+1)=3x+(\frac{2}{3})$

Hence, $(f o g)(x)=3x+(\frac{2}{3})$

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3 years ago

Fill in the blanks<br> 3 over 8 = 15 over something

Viktor [21]

$\frac{3}{8}= \frac{15}{x} \\ \frac{3}{8} \frac{*5}{*5}= \boxed{\frac{15}{40}}$

4 0

4 years ago

Read 2 more answers