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Taya2010 [7]
3 years ago
11

Is f(x)=x^4-x^2 even or odd

Mathematics
1 answer:
Arisa [49]3 years ago
6 0
Answer: i think it’s even.

Explanation:

Since the exponent are both even and even number - even number = even number.

Ex: 2^4 - 2^2 = 16 - 4 = 12 which is an even number
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Explain how the following diagram demonstrates the pythagorean theorem?
Yuliya22 [10]

Answer:

the largest block represents the hypotenuse which would be c² the smallest can either be a or b and the block thats left over will be the letter you didn't use for the small block so in terms the blocks represents a²+b²=c²

7 0
3 years ago
Read 2 more answers
The formula s= sqrt SA/6
ikadub [295]
For this case we have the following equation:
 s = root (S.A / 6)
 Substituting values we have:
 For S.A = 180:
 s = root (180/6)
 s = root (30)
 For S.A = 120:
 s = root (120/6)
 s = root (20)
 s = root (4 * 5)
 s = 2 * root (5)
 Subtracting both values we have:
 root (30) - 2 * root (5)
 Answer:
 
root (30) - 2 * root (5)
 
option 2
3 0
3 years ago
The larger of to numbers is 12 more than the smaller. Their sum is 84. What are the two numbers?
Nataly_w [17]
36 and 48

a = b+12
a+b = 84

(b+12) + b =84
2b +12 = 84
2b = 72
b= 36

a = b + 12
a = 36 + 12
a = 48
3 0
4 years ago
How to solve 3(×-5)-5=23​
USPshnik [31]

Step 1: Simplify both sides of the equation.

3(x−5)−5=23

(3)(x)+(3)(−5)+−5=23(Distribute)

3x+−15+−5=23

(3x)+(−15+−5)=23(Combine Like Terms)

3x+−20=23

3x−20=23

Step 2: Add 20 to both sides.

3x−20+20=23+20

3x=43

Step 3: Divide both sides by 3.

3x /3  =  43 /3

x= 43 /3

4 0
3 years ago
Read 2 more answers
Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers
Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

  • b is the opposite of the sum of the roots
  • c is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

  • 4+(-2) = 4-2 = 2 \implies b = -2
  • 4 \cdot (-2) = -8 \implies c = -8

So, the equation is x^2-2x-8=0

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

  • \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}
  • \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}

And so the equation is

x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0

In order to have integer coefficients, you can multiply both sides of the equation by 8:

8x^2 - 10 + 3 = 0

5 0
3 years ago
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