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4 years ago

Find the solution to the equation below. 2x^2+3x-20=0

Mathematics

2 answers:

icang [17]4 years ago

8 0

C maybe bro I’m not really sure tho think I’m messing up

Sphinxa [80]4 years ago

4 0

<h2>Answer:</h2>

<u>The right choice is </u><u>(D) x= -4, 5/2</u>

<h2>Step-by-step explanation:</h2>

2x^2+3x-20=0

By factoring the expression we get

2x²2 +8x−5x−20=0

(x+4) (2x−5) = 0

Now

(x+4) = 0 OR x = -4

and

(2x-5) = 0 OR x = 5/2

S the solutions are

x= -4 and x = 5/2

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Check:

$\begin{array}{rclcrcl}4.85\times2+0.89\times6 & =& 15.04 & \qquad &2+6&=&8\\9.70+5.34 & = & 15.04 & \qquad &8&=&8\\15.04& = & 15.04 & & & & \\\end{array}$

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