Choose a value for n that will make the sum negative. 15 + n

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

Answer:

n > -15

Step-by-step explanation:

15 + n

15 + -16 (at least)

n = -1

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Only the circled ones

ozzi

2.

M must be (0,0) since it coincides with the origin
R must be (a+b, √(a²-b²)).
The x-coordinate is b from A translated to the right by a.
The y-coordinate is the same as A.

(I think the square root is there to confuse you).

3.

R(0,0)
C(a,b) (same x as T, same Y as E)

5.

Not sure how to prove that.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=If%20w%3D2x%2C%20then%20%5Cint%5Climits%5E2_0%20%7Bf%282x%29%7D%20%5C%2C%20dx%20%3D" id="TexFo

elena-14-01-66 [18.8K]

First, you should solve for $f(2x)$ , which equals $2*(2x)=4x$ . Now, solve the integral of $f(2x)$ = $2*(2x)=4x$ , to get that $\int\ {(f(2x)=4x)} \, dx= 2x^2$ . You can check this by taking the integral of what you got. Now by the Fundamental Theorem $\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8$ .

This should be the answer to your question, if I understood what you were asking correctly.

8 0

3 years ago

What is the equation of the following graph in vertex form?

Elza [17]

$\bf \boxed{y=(x-{{ h}})^2+{{ k}}}\\\\
x=(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\textit{vertex is at 4,-4}\implies 
\begin{cases}
h=4\\
k=-4
\end{cases}\implies y=(x-4)^2+(-4)
\\\\\\
\boxed{y=(x-4)^2-4}$