For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
u need to put a picture so we know what your talking about
<span>The ramp forms a right triangle with legs 5 and 22.
Find the length of the hypotenuse using the Pythagorean theorem,
c=raiz((5)^2+(22)^2)=</span><span>
<span>22.56 ft
Answer
</span></span> the ramp is 22.56 ft long.
1 to 5 you most likely have to add 36 x the number but the fractions I don't know
