Answer: 300
Step-by-step explanation:
Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.
i.e, Total CD's he has now = 6,000
Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.
Then , the proportion of defective( D) CD's = 
Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)
= 6000 x 0.05
=300
Hence, the number of CDs in the shipment are likely to be defective =300
Answer = -16
I have attached a picture below
37.68 is the correct answer
The answer is A because you would do 79 x 0.05 which equals 3.95 . So you subtract 3.95 from 79 which is 75.05 minus 50 equal to 25.05