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kirill [66]
3 years ago
6

Please help with this question

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

The maximum revenue will be R=\$25,000 at price p=\$100.

Step-by-step explanation:

Given:

R=-2.5p^2+500p

Find the vertex of the parabola represented by given equation:

p_v=\dfrac{-b}{2a}=\dfrac{-500}{2\cdot (-2.5)}=\dfrac{500}{5}=100

When p=\$100, then

R=-2.5\cdot 100^2+500\cdot 100=-2.5\cdot 10,000+50,000=-25,000+50,000=25,000

The maximum revenue will be R=\$25,000 at price p=\$100.

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Allisa [31]
Hey!


Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get y on its own.

<em>Original Equation : </em>
\frac{y}{2} < -3

<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
\frac{2y}{2} < 2 ( -3 )

And we simplify the equation to get our answer.

<em>Old Equation :</em>
\frac{2y}{2} < 2 ( -3 )

<em>New Equation {Changed by Simplification} :</em>
y < -6

<em>So, the equation \frac{y}{2} < -3 simplified is</em>  y < -6.

Hope this helps!


- Lindsey Frazier ♥
8 0
2 years ago
Find the lengths of "x"
yanalaym [24]
Using pythagorean's theorem
a^2+b^2=c^2

a being 3 
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
4 0
2 years ago
Solve the equations. Check your solution.<br> |x-2|=|4+x|
sasho [114]
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3 0
2 years ago
Regina brought 8 7/8 pound of fruit for her family . She brought 3 1/2 pound of oranges and 2 3/4 pound of peaches and some appl
butalik [34]

Answer:

Regina has bought 2\frac{5}{8}\ pounds of apples.

Step-by-step explanation:

Given:

Amount of fruit brought = 8\frac{7}{8}\ pounds

Now given number is in mixed fraction we will convert into improper fraction.

To convert a mixed fraction to an improper fraction, we will Multiply the whole number part by the fraction's denominator.  Add that to the numerator,Then write the result on top of the denominator.

So we can say that;

8\frac{7}{8}\ pounds can be Rewritten as \frac{71}{8}\ pounds

Amount of fruit brought = \frac{71}{8}\ pounds

Also given:

Amount of oranges bought = 3\frac12\ pounds

3\frac12\ pounds can be Rewritten as \frac{7}{2}\ pounds

Amount of oranges bought =  \frac{7}{2}\ pounds

Amount of peaches bought = 2 \frac34\ pounds

2 \frac34\ pounds can be Rewritten as \frac{11}{4}\ pounds

Amount of peaches bought =  \frac{11}{4}\ pounds

We need to find amount of apples bought by Regina.

Solution:

Let the amount of apples bought be 'x'

Now we know that;

Amount of fruit brought is equal to sum of Amount of oranges bought and Amount of peaches bought amount of apples.

framing in equation form we get;

\frac{71}{8}=\frac{7}{2}+\frac{11}{4}+x\\\\x=\frac{71}{8}-\frac{7}{2}-\frac{11}{4}

Now we will make the denominator common using LCM we get.

x=\frac{71\times 1}{8\times 1}-\frac{7\times4}{2\times4}-\frac{11\times2}{4\times2}\\\\x=\frac{71}{8}-\frac{28}{8}-\frac{22}{8}

Now denominators are same so we will solve the numerator.

x=\frac{71-28-22}{8}\\\\x=\frac{21}{8}\ pounds

Now \frac{21}{8}\ pounds can be Rewritten as 2\frac{5}{8}\ pounds

Hence Regina has bought 2\frac{5}{8}\ pounds of apples.

5 0
3 years ago
If the difference of two numbers is even then so is their sum.
Nutka1998 [239]

Answer and explanation:

Statement - If the difference of two numbers is even then so is their sum.

Let the two even numbers be '2m' and '2n' with m and n are integers.

The difference of two number is

2m-2n=2(m-n)

Now, The sum of the numbers is

2m+2n=2(m+n)

Let m+n=k where k is an integer

Then, 2m+2n=2k which is also an even number as 2 is multiplied with it.

So, If the difference of two numbers is even then so is their sum.

For example -

Let two even number 2 and 4.

The difference is 4-2=2, 2 is even.

The sum is 4+2=6, 6 is even.

4 0
3 years ago
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