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gogolik [260]
3 years ago
10

Axel got on the elevator at the 23rd floor. He rode it up 4 floors to deliver a package, and then down

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

bag on bags mfajakaakallaaf

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Use the Distributive property to solve the equations.
Zanzabum

Answer:

Follow the steps I did in the explanation.

Step-by-step explanation:

It says to evaluate the equation :-

3.2 = 4/5(b - 5)

3.2 = (4/5 × b) + (4/5 × -5)

3.2 = 4/5b - 4

3.2 + 4 = 4/5b

5/4 × 7.2 = b

9 = b

Hope this helps, thank you :) !!

7 0
3 years ago
Read 2 more answers
An item is priced at $14.61. If the sales tax is 8%, what does the item cost including sales tax?
liubo4ka [24]

Answer:

(1.08)($14.61) = $15.78

4 0
3 years ago
The formula I = PRT where I = Interest, P = Principal, R = Rate, and T = rime use to calculate the amount of simple interest ear
monitta
\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\\
r=rate\to r\%\to \frac{r}{100}\\
t=years
\end{cases}
\\\\\\
I=Prt\implies \cfrac{I}{Pr}=t
3 0
3 years ago
Anyone knows how to do questions 7 and 8? 15 pts!!
Oksi-84 [34.3K]
7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: 2x^2-4x+5. With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

2x^2+5=4x\\\\ 2x^2-4x+5=0

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)

Multiplying by (2-1) in the both sides:

(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ... Repeating the process, we obtain: ...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}
3 0
4 years ago
Read 2 more answers
If a data set has only 1 outlier which value will always change when the outlier is excluded
blagie [28]

The median may stay the same.

The range will always change.

I dont think the last 2 will always change.

7 0
3 years ago
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