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Reptile [31]
3 years ago
9

6 + (9 − 1) 2 ÷ 4 the 2 is an exponent

Mathematics
1 answer:
zmey [24]3 years ago
4 0
6+(9-1)^2/4 = 22
______________[
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What is the product?
Kamila [148]
= (-5)(-3)(-7)(2)(0.5) \\ = (15) (-17)(2)(0.5) \\ = ( -105)(2)(0.5) \\  = (-210)(0.5) \\ =-105
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3 years ago
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Please help..... Simplify each equation.
dybincka [34]
A) this is the simplified form
( {x}^{3}  + 3 {x}^{2}  - 6) + ( {x}^{2} - x + 7) \\  =  {x}^{3}   + 3 {x}^{2}  - 6 +  {x}^{2}  - x + 7 \\  =  {x}^{3}  + 4 {x}^{2}  - x + 1
b)
(5 {x}^{2}  - 4x + 7) - ( {x}^{2}  - 2x - 5) \\  = 5 {x}^{2}  - 4x + 7 -   {x}^{2}  + 2x + 5 \\  = 4 {x}^{2}   - 2x + 12
8 0
3 years ago
If f(x)= 5x -7, what is f(3)?
Gemiola [76]

Answer:

8

Step-by-step explanation:

f(x) = 5(3) - 7

f(x) = 15 - 7

f(x) = 8

4 0
3 years ago
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8x - 5y = 30<br> Solve for y
charle [14.2K]
The answer is y=8/5x-6
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3 years ago
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Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
Sauron [17]

Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

8 0
3 years ago
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