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2 years ago

2x(5-x)+3x^2 shown work please

Mathematics

2 answers:

nekit [7.7K]2 years ago

5 0

$\\ \rm\Rrightarrow 2x(5-x)+3x^2$

$\\ \rm\Rrightarrow 10x-2x^2+3x^2$

$\\ \rm\Rrightarrow 10x+(-2+3)x^2$

$\\ \rm\Rrightarrow 10x+x^2$

$\\ \rm\Rrightarrow x^2+10$

Liula [17]2 years ago

4 0

2x(5－x)＋3x²
＝x(2(5－x)＋3x)
＝x(10－2x＋30x)
＝x(10＋x)

OR

2x(5－x)＋3x²
＝10x－2x²＋3x²
＝10x＋x²

Hope my answer helped u :)

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2 years ago

Add -54 + 18. -36 -44 -72

Illusion [34]

Answer:

A. -36

*The answer must have a negative sign.*

Step-by-step explanation:

First, you had to add/subtract by the integers.

Then, you subtract by the numbers.

$54-18=36$

It change positive to negative sign.

$=-36$

Hope this helps!

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2 years ago

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In science class, Liz learned that trees help make the oxygen that people breathe. One tree makes about 250 pounds of oxygen eac

klio [65]

Answer: The answer is 8000 pounds, or 4 tons

Step-by-step explanation:

This is true because each tree makes about 250 pounds of oxygen. She counted 32 so.....

(32)(250)=8000

then convert 8000 pounds to tons and you get 4 tons

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2 years ago

What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?

joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

$T_{n}=a+(n-1)d$

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now $T_{23}= a + (n-1)d$

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

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3 years ago

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

6 0

3 years ago