Question

g (3 points)Set up but do no solve the integral required to calculate the volume formed by rotating the region bounded by f(x) = 1/x,g(x) = 1/x^3, andx= 2, andx= 4 around they-axis. Also draw a picture of the region (non-revolved).

Answer 1

Answer:

Hello,

Step-by-step explanation:

$\displaystyleV=2*\pi*\int\limits^4_2 {(\dfrac{1}{x}-\dfrac{1}{x^3} )*x } \, dx \\=2*\pi*\int\limits^4_2 {(1-\dfrac{1}{x^2} ) } \, dx \\=2*\pi* [x+\dfrac{1}{x}]^4_2\\\\\boxed{V=\dfrac{7\pi}{2}}$