Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
The answer for the first equation is,
B. 11
The answer for the second equation is,
D.none of these.
4:3 8:6 24:18 20:15 is the complete ratio table.
1) y= -4x+c
2) y= 3x+c replace x and y to find c , 5=3(2)+c
C= -1
Y=3x-1
3) find slope first m=y2-y1/x2-x1 = 0-(-1)/-2-1 = 1/-3 and now you have y= -1/3x+c to find c just replace any of the given points , 0= -1/3(-2)+c
C= -2/3 and so y= -1/3x-2/3
4) DO THE SAME STEP AS NUMBER 3 and enjoy!
