Answer:
Step-by-step explanation:
4 quarters
1 dime
Answer: See below
Step-by-step explanation:
When you see that something is to the power of a negative number, it is another way of saying 1 over.
![(2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}](https://tex.z-dn.net/?f=%282x-2%29%5E-%5E3%3D%5Cfrac%7B1%7D%7B%282x-2%29%5E3%7D%20%3D%5Cfrac%7B1%7D%7B%282x-2%29%284x%5E2-8x%2B4%29%7D%20%3D%5Cfrac%7B1%7D%7B8x%5E3-8x%5E2%2B8x-8%7D)
SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get
|f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
-0.4 < x - 2 < 0.4
-0.4+2 < x < 0.4+2
1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
</span>
The answer is 5.6! Hope I helped!