200 because 600 divided by 3 is 2 and if it one out of 3 then it is going to be 2
Answer:
In the long run, ou expect to lose $4 per game
Step-by-step explanation:
Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.
Assuming X be the toss on which the first head appears.
then the geometric distribution of X is:
X
geom(p = 1/2)
the probability function P can be computed as:

where
n = 1,2,3 ...
If I agree to pay you $n^2 if heads comes up first on the nth toss.
this implies that , you need to be paid 

![\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20%5E%7Bn%7D_%7Bi%3D1%7D%20n%5E2%20P%28X%3Dn%29%20%3DVar%20%28X%29%20%2B%20%5BE%28X%29%5D%5E2)
∵ X
geom(p = 1/2)








Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6
= $4
∴
In the long run, you expect to lose $4 per game
Two triangles are said to be congruent when the have the same sides and the same angles. When a figure is dilated by a value, the size of that figure changes.
Therefore, when Triangle MNO is reflected across the y-axis and then dilated by a scale factor of 1.8 to form triangle MꞌꞌNꞌꞌOꞌꞌ, the two triangles are similar but not congruent.
Answer:

Step-by-step explanation:
The probability that a randomly selected cap will not be green is equal to the number of non-green caps divided by the total number of caps.
Since there are 100 caps total and 22 are green, there must be
non-green caps.
Divide this by the total number of caps (100) to get the probability that a randomly selected cap will not be green:

Simplify by dividing both the numerator and denominator by 2:
