¹³/₁₂
<h3>
Further explanation</h3>
<u>Given:</u>
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = ? \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%3F%20%5C%20%7D)
- A fraction represents part of a whole.
- A fraction consists of a numerator and a denominator. i.e.,
. - The numerator = the number of equal parts of a whole.
- The denominator = the total number of parts that make up said whole.
From the problems above, the denominator or the bottom numbers are still different. We use the Least Common Multiple (or LCM) to equalize the denominator.
- Multiples of 3:
![\boxed{ \ \{3, 6, 9, 12, 15, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B3%2C%206%2C%209%2C%2012%2C%2015%2C%20...%20%5C%7D%20%5C%20%7D)
- Multiples of 4:
![\boxed{ \ \{4, 8, 12, 16, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B4%2C%208%2C%2012%2C%2016%2C%20...%20%5C%7D%20%5C%20%7D)
- Multiples of 6:
![\boxed{ \ \{6, 12, 18, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B6%2C%2012%2C%2018%2C%20...%20%5C%7D%20%5C%20%7D)
Hence, the LCM for 3, 4, and 6 is 12.
We change the denominator for each fraction to 12.
![\boxed{ \ \frac{1}{6} \rightarrow \frac{multiply \ by \ 2}{multiply \ by \ 2} \rightarrow \frac{2}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%202%7D%7Bmultiply%20%5C%20by%20%5C%202%7D%20%5Crightarrow%20%5Cfrac%7B2%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{2}{3} \rightarrow \frac{multiply \ by \ 4}{multiply \ by \ 4} \rightarrow \frac{8}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B2%7D%7B3%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%204%7D%7Bmultiply%20%5C%20by%20%5C%204%7D%20%5Crightarrow%20%5Cfrac%7B8%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{1}{4} \rightarrow \frac{multiply \ by \ 3}{multiply \ by \ 3} \rightarrow \frac{3}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B4%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%203%7D%7Bmultiply%20%5C%20by%20%5C%203%7D%20%5Crightarrow%20%5Cfrac%7B3%7D%7B12%7D%20%5C%20%7D)
Then we continue adding fractions.
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{2}{12} + \frac{8}{12} + \frac{3}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B2%7D%7B12%7D%20%2B%20%5Cfrac%7B8%7D%7B12%7D%20%2B%20%5Cfrac%7B3%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \boxed{ \ \frac{13}{12} \ } \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cboxed%7B%20%5C%20%5Cfrac%7B13%7D%7B12%7D%20%5C%20%7D%20%5C%20%7D)
Thus, the result is ![\boxed{ \ \frac{13}{12} \ or \ 1\frac{1}{12}\ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B13%7D%7B12%7D%20%5C%20or%20%5C%201%5Cfrac%7B1%7D%7B12%7D%5C%20%7D)
<h3>Learn more</h3>
- ²/₇m - ¹/₇= ³/₁₄ solve step by step brainly.com/question/4853649
- 100 is 1/10 of what? brainly.com/question/96535
- Mr. Frye distributed his money equally among his 4 children for their weekly allowance brainly.com/question/13174288#
Keywords: the sum of ¹/₆, ²/₃, and ¹/₄, fraction, adding, numerator, denominator, still different, LCM
Answer:
If friction did not exist, it would be hard for us to slow down in running, or putting breaks on a car, and more!
If friction did not exist, your car will slide down the road even if you try your best to put the brakes on a car. Friction is a very important force to slow down things that are moving very fast
Step-by-step explanation:
Hoped this helped.
![GeniusUser](https://tex.z-dn.net/?f=GeniusUser)
the gardener would need (1 + 1/6) liters of water to water the whole garden.
<h3>How much water would the gardener need to water the whole garden?</h3>
Here we know that the gardener needs 1/3 of a liter of water to water 2/7 of a garden.
Then we have the relation:
1/3 L = 2/7 of a garden.
Now, we want to get a "1 garden" in the right side of the equation, then we can multiply both sides by (7/2), so we get:
(7/2)*(1/3) L = (7/2)*(2/7) of a garden
(7/6)L = 1 garden.
(1 + 1/6) L = 1 garden
This means that the gardener would need (1 + 1/6) liters of water to water the whole garden.
If you want to learn more about fractions:
brainly.com/question/11562149
#SPJ1
You would do 17 times 5.5 = 93.5, so the volume of the ice cream cone would be 93.5 centimeters. I’m assuming that’s the right answer but you might want to get a second opinion.
Answer:
from side a _2,4.5
from side b _-4
5,-2.
hope this will be helpful for you.