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3 years ago

Estimate the product of 25.311 × 4.65.

2 answers:

8 0

The best way is to round off the two multiplicands, not to round off the "exact" answer.

Round off 25.311 to 25 and round off 4.65 to 5. Then the approx. product is 125.

Damm [24]3 years ago

3 0

The answer would be:

117.69615

BUT since it's asking you to estimate, I would put:

"about 117.69"

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What is 100/ 5 i need help asap

zepelin [54]

Answer:

Step-by-step explanation:

You can take a 0 off of 100.

10/5=2

Add the 0 back to the end

20 is your answer.

3 0

3 years ago

Which of the following expressions have equivalent solutions?

MakcuM [25]

1. -3.8
2. -242/67
3. -11368
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5 0

3 years ago

Read 2 more answers

IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s

butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 116, \sigma = 16$

What are the z scores that separate the unusual IQ scores from those that are usual?

If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

What are the IQ scores that separate the unusual IQ scores from those that are usual?

Those IQ scores are X when Z = -2 and X when Z = 2. So

Z = -2

$Z = \frac{X - \mu}{\sigma}$

$-2 = \frac{X - 116}{16}$

$X - 116 = -2*16$

$X = 84$

Z = 2

$Z = \frac{X - \mu}{\sigma}$

$2 = \frac{X - 116}{16}$

$X - 116 = 2*16$

$X = 148$

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

8 0

3 years ago

Read 2 more answers

This is a 2 part question. Need help with both questions please! Use the triangle for both parts of the question. Click on the f

ollegr [7]

Answer:

Part A) Option A. QR= 3 cm

Part B) Option B. SV=6.5 cm

Step-by-step explanation:

step 1

Find the length of segment QR

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem Triangle QRW and Triangle QSV are similar by AA Similarity Theorem

$\frac{QR}{QS}=\frac{QW}{QV}$

we have

$QS=9\ cm$ ---> because S is the midpoint QT (QS=TS)

$QW=2\ cm$ --->because V is the midpoint QU (QW+WV=VU)

$QV=6\ cm$ --->because V is the midpoint QU (QV=VU)

substitute the given values

$\frac{QR}{9}=\frac{2}{6}$

solve for QR

$QR=9(2)/6=3\ cm$

step 2

Find the length side SV

we know that

The Mid-segment Theorem states that the mid-segment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this mid-segment is half the length of the third side

In this problem

S is the mid-point side QT and V is the mid-point side QU

therefore

SV is parallel to TU

and

$SV=(1/2)TU$