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gregori [183]
3 years ago
7

Let A=3i-j-4k,B=-2i+4j-3k and C=i+2j-k compute 2A-B+3C​

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

A = 3i - j - 4k

B = -2i + 4j - 3k

C = i + 2j - k

2A - B + 3C =

= 2(3i - j - 4k) - (-2i + 4j - 3k) + 3(i + 2j - k) =

= 6i - 2j - 8k + 2i - 4j + 3k + 3i + 6j - 3k =

= 6i + 2i + 3i - 2j - 4j + 6j - 8k + 3k - 3k =

= <u>1</u><u>1</u><u>i</u><u> </u><u>-</u><u> </u><u>8</u><u>k</u>

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5 1/4 + 2 3/4 = what is the summ
Burka [1]
5 + 2 = 7
1/4 + 3/4 = 1
7 + 1 = 8
Your answer is 8
7 0
4 years ago
Read 2 more answers
Which of the following is a factor of 2xy + 8y − 8x − 32?
muminat
You could start by eliminating wrong answer(s):

(a) 5 is definitely not a factor of the given <span>2xy + 8y − 8x − 32,

(d) x^2 - 4x + 16 (not x2 - 4x + 16) is not a factor (it has no y terms)

On the other hand:

(b) 2 definitely divides evenly into </span>2xy + 8y − 8x − 32:  2(<span>xy + 4y − 4x − 16)

(c) x + 4 divides evenly into both xy + 4y and -(4x + 16):
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4 0
3 years ago
Multiply the following<br> (-7pq^2r^3) * (-13p^3q^2r)
artcher [175]

Answer:

91p^{1+3q^{2r}}q^{2r^3}

Step-by-step explanation:

  (-7pq^2r^3) * (-13p^3q^2r)

= 91p^{1+3q^{2r} }*q^{2r^{3} }

= 91p^{1+3q^{2r}}q^{2r^3}

7 0
3 years ago
A grocery store sells three different quantities of sugar. A 1-pound bag costs $1.10, a 2-pound bag costs $1.92, and a 3-pound b
Mashcka [7]
$1.10 per pound for the 1-pound bag.
$0.96 per pound for the 2-pound bag.
$0.92 per pound for the 3-pound bag.

As the quantity of sugar increases, the unit cost decreases.
8 0
4 years ago
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malfutka [58]

Answer:

A no-doest pass the vertical line test

Step-by-step explanation:

the vertical line test is a test saying any line is functional if when several vertical lines are drawn, the function does not pass through any line more than once

hope this helps:)!

3 0
3 years ago
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