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gregori [183]
3 years ago
7

Let A=3i-j-4k,B=-2i+4j-3k and C=i+2j-k compute 2A-B+3C​

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

A = 3i - j - 4k

B = -2i + 4j - 3k

C = i + 2j - k

2A - B + 3C =

= 2(3i - j - 4k) - (-2i + 4j - 3k) + 3(i + 2j - k) =

= 6i - 2j - 8k + 2i - 4j + 3k + 3i + 6j - 3k =

= 6i + 2i + 3i - 2j - 4j + 6j - 8k + 3k - 3k =

= <u>1</u><u>1</u><u>i</u><u> </u><u>-</u><u> </u><u>8</u><u>k</u>

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