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Ilia_Sergeevich [38]
2 years ago
14

There are 11 books on a shelf. 3 of these books are new. The rest of them are used.

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
4 0
Sooo , 8? Is there more to the question
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Which classification describes the following system of equations?
wolverine [178]

A consistent and independent system of equations describes the given system of equations.

The consistent and independent system of equations are given below.

  • 12x+5y-3z= 36
  • x-2y+4z=3
  • 9x-10y+5z = 27

<h3>What is a consistent independent equation?</h3>

A consistent equation is a system of linear equations that is consistently unbiased when it has precisely one solution. While this is the case, the graphs of the lines within the system move at exactly one point. In inconsistent, a system of linear equations is inconsistent if it has no solutions.

Learn more about the system of equations here brainly.com/question/13729904

#SPJ10

5 0
2 years ago
Help me please anyone I ready don’t know this?
goldfiish [28.3K]
It looks like you have number 1 correct.

For number 2, what is alike is the exponent of 2. To combine them, add them together. You can do this because they are like terms (aka have the same variable and exponent)

 3-4-1= -2. The answer is -2x^2

For number 3, those are not like terms. They either do not have the same variable (x or y) or they do not have the same exponent (1 or 2)

Both the exponent and the variable have to be the same for it to be a like term.
3 0
3 years ago
I NEED HELP FAST!!! <br> 3x^3(4x^4+5x^2-2x-9+2x^2) <br><br><br> (Not multiple choice btw)
SIZIF [17.4K]

Answer:

12x^7+21x^5-33x^3

Step-by-step explanation:

12x^7+15x^5-6x^3-27x^3+6x^5

12x^7+21x^5-33x^3

6 0
3 years ago
Find the perimeter. Simplify your answer.<br> 3x+7<br> 3x+7<br> 2x-3
Lera25 [3.4K]

2(3x + 7) + (2x - 3) =

= 6x + 14 + 2x - 3 =

= 6x + 2x + 14 - 3 = <u>8</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>1</u> ← the end

8 0
2 years ago
A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
V125BC [204]

We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

(the first equality is Bayes' theorem)

b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

4 0
3 years ago
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