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zavuch27 [327]
3 years ago
13

Which one is greatest to least?

Mathematics
1 answer:
Reil [10]3 years ago
8 0

Answer:

the seacond answer

Step-by-step explanation:

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Soft-drink cans are filled by an automated filling machine and the standard deviation is 0.5 fluid ounces assume that the fill v
evablogger [386]
A.) For n independent variates with the same distribution, the standard deviation of their mean is the standard deviation of an individual divided by the square root of the sample size: i.e. s.d. (mean) = s.d. / sqrt(n)
Therefore, the standard deviation of of the average fill volume of 100 cans is given by 0.5 / sqrt(100) = 0.5 / 10 = 0.05

b.) In a normal distribution, P(X < x) is given by P(z < (x - mean) / s.d).
Thus, P(X < 12) = P(z < (12 - 12.1) / 0.05) = P(z < -2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275

c.) Let the required mean fill volume be u, then P(X < 12) = P(z < (12 - u) / 0.05) = 1 - P(z < (u - 12) / 0.05) = 0.005
P(z < (u - 12) / 0.05) = 1 - 0.005 = 0.995 = P(z < 2.575)
(u - 12) / 0.05 = 2.575
u - 12 = 2.575 x 0.05 = 0.12875
u = 12 + 0.12875 = 12.12875
Therefore, the mean fill volume should be 12.12875 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.

d.) Let the required standard deviation of fill volume be s, then P(X < 12) = P(z < (12 - 12.1) / s) = 1 - P(z < 0.1 / s) = 0.005
P(z < 0.1 / s) = 1 - 0.005 = 0.995 = P(z < 2.575)
0.1 / s = 2.575
s = 0.1 / 2.575 = 0.0388
Therefore, the standard deviation of fill volume should be 0.0388 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.

e.) Let the required number of cans be n, then P(X < 12) = P(z < (12 - 12.1) / (0.5/sqrt(n))) = 1 - P(z < (12.1 - 12) / (0.5/sqrt(n))) = 0.01
P(z < 0.1 / (0.5/sqrt(n))) = 1 - 0.01 = 0.99 = P(z < 2.327)
0.1 / (0.5/sqrt(n)) = 2.327
0.5/sqrt(n) = 0.1 / 2.327 = 0.0430
sqrt(n) = 0.5/0.0430 = 11.635
n = 11.635^2 = 135.37
Therefore, the number of cans that need to be measured such that the average fill volume is less than 12 fluid ounces be 0.01

8 0
3 years ago
(2^3)^2 (2^-2) / (2^2) (2^0)
Dmitry [639]

Answer:

(2^3)^2 (2^-2) / (2^2) (2^0)

{2}^{3}  \times  {2}^{3}  \times 0 \div  {2}^{2}  \times 1 = 0

3 0
3 years ago
Read 2 more answers
PLEASE HURRYY I GIVE BRAINLIEST!!!
Illusion [34]

Answer:

16x+9

Hope this helps:)

8 0
3 years ago
Translate the phrase "in 3 years" into algebraic terms
Semenov [28]

Answer:

In three years can be into algebraic terms as:  3 + x. Where 'x' comes to be today's age.

For example, my age in three years will be:

If I'm 24 years right now, My age in three years = 3 + x ⇒ My age in three years = 3 + 24 = 27.

3 0
3 years ago
Work out these approximate conversions.
Anvisha [2.4K]

Answer:

0.002 km

Step-by-step explanation:

5 0
2 years ago
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