Answer:
difficult but easy do it yourself you can do you can do you can do bro ...
Two rays sharing a common endpoint is the vertex.
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
12 teams
Step-by-step explanation:
We know that 38 players can fit into 4 groups, 8 times ...
32 divide 8 = 4
We have the number with 96, and we need to find the groups
we do the same as done with the first one...
because 32 divided by 8 is 4
we do
96 divide 8 = 12
aswell
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<em>hope this helped : )</em></u></h2>
