Answer:
1
Step-by-step explanation:2 and 6 are the first ones in each set so 6-2 is 4.4 and 1 are the second ones in each set 1-4 is -3 4+-3 is 1.
Answer:
Step-by-step explanation:
multiply 1/3 by x and 3
The answers are complex numbers...
Here's why...
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p+q=18
pq=82
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Therefore:
p=18-q
p=82/q
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Therefore:
18-q=82/q
q(18-q)=q(82/q)
18q-q²=82
(-1)(18q-q²)=82(-1)
q²-18q=-82
(q-9)²-9²=-82
(q-9)²-81=-82
(q-9)²=-82+81
(q-9)²=-1
q-9=-√(-1)=-i
q-9=√(-1)=i
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Therefore:
q=9-i
q=9+i
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ANSWERS:
When q=9-i, p=9+i
When q=9+i, p=9-i
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Proof:
p+(9-i)=18
p+9-i=18
p=18-9+i
p=9+i
....
p+(9+i)=18
p+9+i=18
p=18-9-i
p=9-i
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More proofs:
p=82/(9+i)
p=(82/(9+i))*((9-i)/(9-i))
p=(82(9-i))/(81-9i+9i-i²)
p=(82(9-i))/(81-(-1))
p=(82(9-i))/82
p=9-i
---------------
p=82/(9-i)
p=(82/(9-i))*((9+i)/(9+i))
p=(82(9+i))/(81+9i-9i-i²)
p=(82(9+i))/(81-(-1))
p=(82(9+i))/82
p=9+i
Answer:
factors are <em>(x-1),(x+2),(x+4),(x+3)</em>
Answer:
Step-by-step explanation:
Normally, in a problem like this one, you'd be given a couple of x-values at which to evaluate the function. Since you didn't do that here, I'll just invent a few: {-1, 0, 7, 11}.
For x = -1: substitute -1 for x in f(x) = x^2 -3x+2: f(-1) = (-1)^2 - 3(-1) + 2 = 6:
f(-1) = 6
Next:
f(0) = 0 - 0 + 2 = 2, so f(0) = 2
For x = 7, substitute 7 for x in f(x) = x^2 -3x+2: f(7) = 49 - 21 + 2 = 30 = f(7)
For x = 11, f(11) = 121 - 33 + 2 = 90 = f(11)
