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777dan777 [17]
2 years ago
6

PLEASE HELP ASAP will give brainliest

Mathematics
1 answer:
sineoko [7]2 years ago
8 0

Step-by-step explanation:

3n-5=(-8*6)+(-8*5n) distributive property

3n-5=-48-40n

3n+40n=-48+5 add property

43n=-43 add property

43n/43=-43/43 division property

n=-1

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What is the equation line that passes through the point (-6,-5) and has a slope of -1\2
tensa zangetsu [6.8K]
If the y intercept isn't -5 go to ur coordinate that is given and find where the y intercept is and plug in the y intercept to y=mx+b
6 0
3 years ago
Find the area of a square with a perimeter of 45cm
Stolb23 [73]

Answer:

the area for the square is 126.56cm²:

8 0
3 years ago
(4x-4)+(3x-2)+(2x+6)=180
Ahat [919]

Answer:

x=20

Step-by-step explanation:

Let's solve your equation step-by-step.

4x−4+3x−2+2x+6=180

Step 1: Simplify both sides of the equation.

4x−4+3x−2+2x+6=180

4x+−4+3x+−2+2x+6=180

(4x+3x+2x)+(−4+−2+6)=180(Combine Like Terms)

9x=180

9x=180

Step 2: Divide both sides by 9.

9x

9

=

180

9

x=20

Answer:

x=20

6 0
2 years ago
Read 2 more answers
What is the value of x in the equation 1/2x - 2/3 y = 30, when y = 15
hammer [34]

Answer:

Step-by-step explanation:

1/2x - 2/3 × 15 = 30

1/2x - 10 = 30

1/2x = 30 + 10

1/2x = 40

x = 40 × 2

x = 80

hope this helps

plz mark it bas brainliest!!!!!!!!!

6 0
3 years ago
Read 2 more answers
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
2 years ago
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