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mihalych1998 [28]
3 years ago
13

The n number of homeruns hit during the regular season by a certain baseball player can be modeled by the function n(x) =3/4x, w

here x is the number of games that have been played. Find the average rate of change from game 12 to game 60.
Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

The average rate of change is equal to \frac{3}{4}\frac{homeruns}{game}

Step-by-step explanation:

we have

n(x)=\frac{3}{4}x -----> this is a linear direct variation

we know that

The rate of change of a linear variation is a constant

The rate of change of a linear variation is equal to the slope of the line

In this problem the slope of the line is equal to m=\frac{3}{4}\frac{homeruns}{game}

therefore

The average rate of change is equal to \frac{3}{4}\frac{homeruns}{game}

<u>Verify</u>

the average rate of change is equal to

\frac{n(b)-n(a)}{b-a}

In this problem we have

n(a)=n(12)=\frac{3}{4}(12)=9\ homeruns  

n(b)=n(60)=\frac{3}{4}(60)=45\ homeruns  

a=12\ games

b=60\ games

Substitute

\frac{45-9}{60-12}=\frac{3}{4}\frac{homeruns}{game}

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-8 equals x + 11 / -2
slava [35]
  • If the equation is -8=x+\frac{11}{-2}:

-8=x+\frac{11}{-2}\\-8=x-\frac{11}{2}\\-8+\frac{11}{2}=x-\frac{11}{2}+\frac{11}{2}\\-\frac{16}{2}+\frac{11}{2}=x\\x=-\frac{5}{2}=-2\frac{1}{2}

  • If the equation is -8=\frac{x+11}{-2}:

-8=\frac{x+11}{-2}\\-8(-2)=\frac{x+11}{-2}(-2)\\16=\frac{-2(x+11)}{-2}\\16=x+11\\16-11=x+11-11\\x=5

Hopefully the math was self-explanatory. If it is not, please feel free to ask for a step-by-step, in depth explanation, and I will edit my answer to accommodate.

5 0
3 years ago
A rocket carrying fireworks is launched from a hill 60 feet above a lake. The rocket will fall into the lake after exploding at
castortr0y [4]

Answer:

<h3>A) 204m</h3><h3>B) 188m</h3>

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v  = 0

0 = -32t + 96t

32t = 96

t = 96/32

t = 3secs

Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

h(3) = -16(9)+ 288 + 60

h(3) = -144+ 288 + 60

h(3) = 144 + 60

h(3) = 204

Hence the maximum height reached by the rocket is 204m

Get the height after 2 secs

h(t) = -16t^2 + 96t + 60

when t = 2

h(2) = -16(2)^2 + 96(2) + 60

h(2) = -64+ 192+ 60

h(2) = -4 + 192

h(2) = 188m

Hence the height of the rocket after 2 secs is 188m

3 0
3 years ago
If a person can see 6 miles from a height of 25 feet, how far can a person see from a height of 196 feet?
Aleksandr-060686 [28]

Answer:

47,04 miles

Step-by-step explanation:

you can clearly see something 20 feet away that you should be able to see from that distance. If a person can see 6 miles from a height of 25 feet, by dividing 196 by 25 we can get the following calculation

196 ÷ 25 = 7,84

Then you gan multiply

7,84 × 6 = 47,04 miles

Or equal to 75703,542 meters

8 0
3 years ago
Tyler used
Andru [333]

Answer:

3.85 gallons

Step-by-step explanation:

  11/4 gallons /5 x 7

= 2.75 gallons /5  x 7

= 0.55 gallon x 7

= 3.85 gallons

3 0
3 years ago
Read 2 more answers
I need help its math
aksik [14]

15 -  x  = 9
Is the same as

15 - 9 = x
And 15-9=6

X=6
5 0
3 years ago
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