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Ne4ueva [31]
3 years ago
15

The probability that a dancer likes ballet is .35. The probability that the dancer likes tap is .45. The probability that the da

ncer likes both ballet and tap is .30. What is the probability that the dancer likes ballet if we know she likes tap? Question 4 options: .30 .35 .67 .75
Mathematics
1 answer:
Tom [10]3 years ago
3 0

Use the formula for conditional probability.

P(likes ballet | likes tap) = P(likes ballet & tap)/P(likes tap)

... = 0.30/0.45 ≈ 0.67

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You take the number of skull bones, which is 1(2), and add that to the number of jaw bones, which is 0. Giving you a total of 2 bones.

Then you are taking the rib bones 3(2) and finding out that you have 6.

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The seventh grade class supplied bags of snacks and beverages for the school dance. They supplied 50 more beverages than bags of
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Answer: 14 bags of snacks.

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3 years ago
Find the zeros of y = x2 - 6x- 4 by completing the square.
Schach [20]

Answer:

x= 3 plus the square root of 13 or x= 3 minus the square root of 13.

Step-by-step explanation:

Hope this helps!

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3 years ago
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A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find cos B, tanB, and sin B. (Plz I need he
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Answer:

5/13, 12/5, 12/13

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6 0
3 years ago
Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a
Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the  we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = 5*sin(\frac{2*\pi*t}{15} )+6

When Jamie is 9 meters above the ground and rising we have

9 = 5*sin(\frac{2*\pi*t}{15} )+6 or 3/5 = sin(\frac{2*\pi*t}{15} ) = 0.6

which gives sin⁻¹(0.6) = 0.643 =\frac{2*\pi*t}{15}

from where t = 1.536 s

Therefore Jamie is gaining altitude at

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = 1.676 m/s.

(b) Jamie is rising most rapidly when   the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15}) =0, π, 2π

Therefore -sin(\frac{2\pi t}{15} ) = 0 whereby t = 0 or

\frac{2\pi t}{15} = π and t =  7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = - 2/3π m/s which is decreasing

so we try at t = 15 s and we have \frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pim/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0
3 years ago
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