Concurrent is when three or more lines intersect at one point.
Here is a concurrent line.
Answer:
p= -1 or -11
Step-by-step explanation:
if you mean (p+ 6)² = 25;
then we have that:
p + 6 = √ 25: gotten by squaring both sides of the equal sign
which makes
p + 6 = ±5
P= -6 ±5
therefore;
p = -6 + 5 or p = -6 -5
Answer: A. -3x+y>-2 and 2y>x+2
Step-by-step explanation: Graph is shown down below.
Hope this helps you out! ☺
Answer:
![(a)\ 15\textdegree C\\(b)\ After\ 3\ minutes\ and\ 52.5\ Seconds\ from\ start](https://tex.z-dn.net/?f=%28a%29%5C%2015%5Ctextdegree%20C%5C%5C%28b%29%5C%20After%5C%203%5C%20minutes%5C%20and%5C%2052.5%5C%20Seconds%5C%20from%5C%20start)
Step-by-step explanation:
Temperature in the room ![=23\textdegree C](https://tex.z-dn.net/?f=%3D23%5Ctextdegree%20C)
Decrease in the temperature(outdoors)
in
.
Rate of decrease![=8\textdegree C/minute](https://tex.z-dn.net/?f=%3D8%5Ctextdegree%20C%2Fminute)
![Let\ after\ x\ minutes\ temperature\ is\ y\\y=23-8x\ \ \ \ y\geq -9\textdegree C](https://tex.z-dn.net/?f=Let%5C%20after%5C%20x%5C%20minutes%5C%20temperature%5C%20is%5C%20y%5C%5Cy%3D23-8x%5C%20%5C%20%5C%20%5C%20y%5Cgeq%20-9%5Ctextdegree%20C)
(a) After
![y=23-5\times 8\\y=-17\\](https://tex.z-dn.net/?f=y%3D23-5%5Ctimes%208%5C%5Cy%3D-17%5C%5C)
But it is not possible as outdoor temperature is
so after
temperature decrease will not occur.
Hence after
more minutes temperature=![-9\textdegree C](https://tex.z-dn.net/?f=-9%5Ctextdegree%20C)
(b) Let after
temperature is ![-8\textdegree C](https://tex.z-dn.net/?f=-8%5Ctextdegree%20C)
Here ![x=t,\ y=-8\textdegree C](https://tex.z-dn.net/?f=x%3Dt%2C%5C%20y%3D-8%5Ctextdegree%20C)
![-8=23-8x\\8x=23+8\\8x=31\\x=\frac{31}{8}\\x=3.875\ minutes=3\ minutes\ and\ 52.5\ seconds](https://tex.z-dn.net/?f=-8%3D23-8x%5C%5C8x%3D23%2B8%5C%5C8x%3D31%5C%5Cx%3D%5Cfrac%7B31%7D%7B8%7D%5C%5Cx%3D3.875%5C%20minutes%3D3%5C%20minutes%5C%20and%5C%2052.5%5C%20seconds)
Answer:
A 8.42
Step-by-step explanation:
15.99+22.95+19.96+32.67 = 91.57
100.00-91.57 =8.42