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Elenna [48]
3 years ago
13

Pleaseee help help

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0

The angle the golfer went off line from the tee when they  drove the ball

is \phi=28.2 \textdegree because the cosine rule has been applied to calculate the angle

From the question we are told that:

Distance of hole from tee d_h=340yards

Distance to the right d_r=230yards

Ball distance from hole d_b=175 yard

Given that the three points form a triangle x,y,z respectively

Where

d_h=xz

d_r=xy

d_b=yz

Using Cosine Rule

yz^2=xy^2+xz^2-2(xy)(xz)cos\phi

Therefore

cos\phi=\frac{yz^2}{xy^2+xz^2-2(xy)(xz)}

cos\phi=\frac{(175)^2}{230^2+340^2-2(230)(340)}

cos\phi=0.88

\phi=28.2 \textdegree

In conclusion the angle the golfer went off line from the tee when they

drove the ball is mathematically deducted and give as

\phi=28.2 \textdegree

For more information on this visit

brainly.com/question/21856223

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NEED HELP ASAP!!!!!!! WILL MARK CORRECT ANSWER BRAINLIEST!!!!
Ganezh [65]

Answer:

(x + 1)² + (y - 1)² = 1.5625

Step-by-step explanation:

From the picture we see:

The radius is 5 units. Each unit is .25 so the radius is 1.25.

The centre or middle M= ( -1, 1 )

Circle with centre M and radius r :

(x - xM)² + (y - yM)² = r²

xM = -1

yM = 1

r = 1.25

(x - (-1))² + (y - 1)² = (1.25)²

(x + 1)² + (y - 1)² = 1.5625

6 0
4 years ago
How many pairs of parallel faces are shown?<br><br><br> 3<br><br><br> 5<br><br><br> 4<br><br><br> 6
TiliK225 [7]
There are 3 parallel faces shown
5 0
3 years ago
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9/v=3/30 v=__<br> solve the proportion.
Nadya [2.5K]
3/30=9/v
3×3=9
30×3= 90
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8 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

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3 years ago
How to find the mean and the median
maria [59]

The mean you have to add up your numbers first then divide them by the amount of numbers you have .ex. 1+2+3 is 6 then divide so 6÷3 =3   Median is the middle number in list. So put them in order then muddle number is your median. If you have two numbers left add them and divide by 2. That will be your median.

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