x=1, y=2
Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3
5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3
In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3
Add 20 to both sides:{y = 5 - 3 x17 x = 17
Divide both sides by 17:{y = 5 - 3 xx = 1
Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer: {x = 1 y = 2
If a football player runs 5/6 of a mile every 3/4th of a hour, that means every 1/4th a hour he runs 1.5/6th of a mile.
That means every 15 minutes the football player runs .2 of a mile. That means that every hour he runs :
0.8 of a mile!
You find a unit rate by multiplying by 100<span />
Givens
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b = 13
h = 9
Area = b*h
Area = 13*9 = 117 square in
Trapezoid
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Givens
b1=9
b2 = 15
h = 14
Area = (b1 + b2)*h/2
Area = (9 + 15)* 14/2
Area = 24 * 14 / 2
Area = 336/2
Area = 168 square inches.
Rhombus
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I can't see the second number I'll make one up. Redo the questioin and put a the number in
Area = 1/2 * d1 * d2
d1 = 18
d2 = 12 substitute what it really says here.
Area = 1/2 * 18 * 12
Area = 108
