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3 years ago

What is the answer for this question

Mathematics

1 answer:

quester [9]3 years ago

7 0

So there are 6 different numbers you can land on, (1-6). It asked for the probability of rolling under 4. Basically there are only 3 numbers under 4. So the answer would be 3/6 simplified, which is 1/2.

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Gracie earns $7 for each car she washes. she always saves $25 of her weekly earnings. this week, she wants to have at least $65

nata0808 [166]

65 divided by 7 is approximently 9, and 25 divided by 7 is approximently 3, so 9 plus 3 is 12, so Gracie must wash 12 cars to earn enough money to save 25 and spend 65!

7 0

3 years ago

PLEASE HELP!! I’LL MAKE YOU BRAINIEST!

Leokris [45]

Answer:

1. Markup: $2.70, Retail: $20.70

2. Markup: $9.45, Retail: $31.95

3. Markup: $25.31, Retail: $59.00

4. Markup: $24.75, Retail: $99.74

5. Markup: $48.60, Retail: $97.20

6. Markup: $231.25, Retail: $416.25

Step-by-step explanation:

To get the markup price of an item, multiply it by the markup percentage as a decimal. To get the decimal of a percentage, divide the number by 100. For example, 15% would be 0.15. And then to find how much the item has been marked up by, multiply the current price by the decimal.

$18 * 0.15 = $2.70

So $2.70 is the markup. To find the retail price, you need to add the markup price to the current price given.

$18 + $2.70 = $20.70

So your retail price is $20.70. Repeat these steps for each question to get the answers above.

Hope this helps.

7 0

3 years ago

5th grade math. Correct answer will be marked brainliest.

Marat540 [252]

Answer:

0.065

Step-by-step explanation:

64.9 / 1000 = 0.0649 --> 0.065

5 0

2 years ago

Read 2 more answers

An education researcher claims that 58% of college students work year-round. In a random sample of 400 college students, 232

Hatshy [7]

Answer:

The proportion of college students who work year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58% of college students work year-round.

A random sample of 400 college students, 232 say they work year-round.

To test the researcher's claim use a one-proportion z-test.

The hypothesis can be defined as follows:

H₀: The proportion of college students who work year-round is 58%, i.e. p = 0.58.

Hₐ: The proportion of college students who work year-round is 58%, i.e. p ≠ 0.58. C

Compute the sample proportion as follows:

$\hat p=\frac{232}{400}=0.58$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0$

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

$p-value=2\times P(z$

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work year-round is 58%.

6 0

4 years ago

Which statement about isosceles triangles is true?

Paraphin [41]

C- I’m assuming that you meant to say that they have one angle that is equivalent to another
All isosceles triangles have two sides that are of equal length

7 0

3 years ago