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DiKsa [7]
3 years ago
13

What is web browser give answerwhat is web browser ​

Computers and Technology
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

A software application used to access information on the World Wide Web is called a Web Browser.

Explanation:

When a user requests some information, the web browser fetches the data from a web server and then displays the webpage on the user's screen.

You might be interested in
Scientists measure an object’s mass in kilograms and its weight in newtons. If you knowthe amount of mass of an object in kilogr
Phoenix [80]

Answer:

public class WeightCalculator {

   

   private static DecimalFormat df2 = new DecimalFormat("#.##");

   

   public static void main(String args[]){

       //create scanner to receive user input

       Scanner in = new Scanner(System.in);

       //alert user to input mass

       System.out. println("Enter the Mass in Kg");

       //collect the input as a string

       String s = in. nextLine();

       //convert string to double and multiply by 9.8

       Double weight = Double.valueOf(s)* 9.8;

       

       //Print out answer formatted to 2 decimal place

       System.out. println("The Weight is " + df2.format(weight) + "N");

       

       //conditional statement to check if weight is less than 100

       if (weight < 100){

           System.out. println("Oops, it is too light");

       }

       //conditional statement to check if weight is more than 500

       if (weight > 500){

           System.out. println("Oops, it is too heavy");

       }            

   }

}

7 0
4 years ago
Write a function called order() thattakes three parameters, and rearranges the integers referred to sothat the largest is first,
gogolik [260]

Answer: The c++ program to implement order() method is given below.

#include <iostream>

using namespace std;

void order(int a, int b, int c);

int main() {

   int x, y, z;

   cout<<"This program displays numbers in descending order."<<endl;

   do

   {

       cout<<"Enter first number"<<endl;

       cin>>x;

       if(x<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(x<0);

   do

   {

       cout<<"Enter second number"<<endl;

       cin>>y;

       if(y<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(y<0);

   do

   {

       cout<<"Enter third number"<<endl;

       cin>>z;

       if(z<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(z<0);

   order(x, y, z);

   return 0;

}

void order(int a, int b, int c)

{

   if((a>b)&&(a>c))

   {  

       cout<<"Numbers in decreasing order are"<<endl;

       cout<<a<<endl;

           if(b>c)

           {

               cout<<b<<endl;        

               cout<<c<<endl;

           }

           else

           {

               cout<<c<<endl;

               cout<<b<<endl;

           }

   }    

   if((b>a)&&(b>c))

   {  

       cout<<"Numbers in decresing order are"<<endl;

       cout<<b<<endl;

           if(a>c)

           {

               cout<<a<<endl;        

               cout<<c<<endl;

           }

           else

           {

               cout<<c<<endl;

               cout<<a<<endl;

           }

   }    

   if((c>b)&&(c>a))

   {  

       cout<<"Numbers in decreasing order are"<<endl;

       cout<<c<<endl;

           if(a>b)

           {

               cout<<a<<endl;        

               cout<<b<<endl;

           }

           else

           {

               cout<<b<<endl;

               cout<<a<<endl;

           }

   }

       

}

OUTPUT

This program displays numbers in descending order.

Enter first number

12

Enter second number

-9

Invalid input. Enter a positive number.

Enter second number

0

Enter third number

55

Numbers in decreasing order are

55

12

0

Explanation:

The method order() is declared as follows.

void order(int a, int b, int c);

The method is declared void since it does not return any value.

This program is designed to accept 0 and positive integers only. This is implemented by do-while loop while taking user input.

The program uses 3 integer variables to store the user input.

int x, y, z;

The method order() is designed to accept 3 integer parameters. This method is called once user enters valid input.

order(x, y, z);

These numbers are compared in order to display them in descending order.

No variable is used for comparison. The method simply compares the numbers and displays them using multiple if-else statements.

4 0
3 years ago
In what type of attack does the adversary leverage a position on a guest operating system to gain access to hardware resources a
il63 [147K]

Answer:

VM escape attack

Explanation:

<em>In a VM escape attack, the attacker exploits hypervisor vulnerabilities to gain control over resources reserved for other guest operating systems. Services operating on the guest may be exposed to the other attacks, but such attacks can only access data allotted to the same guest. In the event of a buffer overflow or directory traversal or the client in the case of cross-site scripting.</em>

6 0
2 years ago
When you call one of the Scanner class's methods to read a primitive value, such as nextInt or nextDouble, and then call the nex
Rzqust [24]

The answer is true.

Explanation:

The scanner class's methods are the methods in java.util, which allows the user to read values of various types. If the nextLine is issued after a numeric read and the numeric value is at the end of the line, nextLine returns the empty string.

The problem occurs when you click the enter key which is a new line \n character. nextInt() has only the integer but skips the new line \n.

To solve this problem, you have to add the input.nextLine() after reading the int it will consume the \n.

Hence, make input.nextLine(); call after input.nextint(); which reads till end of life.

5 0
4 years ago
To get a sense of your digital footprint, you should: Question 2 options: Google yourself regularly, and monitor what your frien
masha68 [24]
Let us examine the given answers.

a) Google yourself regularly, and monitor what your friends post.
  Verdict: This answer is correct, but it is also necessary to look for yourself on other search engines.

b) Google yourself once a year
  Verdict: Once a year is better than doing nothing, but more than once a year is preferable.

c) Google yourself every five years.
  Verdict: The time interval is too long. Your reputation could easily be damaged, or your identity could be stolen in less than 5 years.

d) Delete all your accounts and start fresh.
   Verdict: This will not solve the problem of having your reputation damaged, or having your identity stolen. Information on the web is preserved ins storage vaults for long periods of time.

Answer: 
Google yourself regularly, and monitor what your friends post. Also, search for your name on other search engines.

3 0
4 years ago
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