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liberstina [14]
3 years ago
9

When you call one of the Scanner class's methods to read a primitive value, such as nextInt or nextDouble, and then call the nex

tLine method to read a string, an annoying and hard-to-find problem can occur.True / False.
Computers and Technology
1 answer:
Rzqust [24]3 years ago
5 0

The answer is true.

Explanation:

The scanner class's methods are the methods in java.util, which allows the user to read values of various types. If the nextLine is issued after a numeric read and the numeric value is at the end of the line, nextLine returns the empty string.

The problem occurs when you click the enter key which is a new line \n character. nextInt() has only the integer but skips the new line \n.

To solve this problem, you have to add the input.nextLine() after reading the int it will consume the \n.

Hence, make input.nextLine(); call after input.nextint(); which reads till end of life.

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A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter
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Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

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2 years ago
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