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Ierofanga [76]
3 years ago
5

Bài 1: Có tất cả bao nhiêu giá trị của m nguyên để hàm số:

Mathematics
1 answer:
denis23 [38]3 years ago
7 0
Voy gvvcfryb teddy y yhcreh
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(9 1/3 + 4 2/3) +7 - (-12)= <br><br> A: 2 and 5/8<br> B: -13 and 13/16<br> C: 14<br> D: 4
SSSSS [86.1K]

Answer:

BIL is the answer to that one day

7 0
4 years ago
In 1970 there were 160 African American women in elected public office in the United States. By 1993 the number had increased to
timama [110]

Answer:

Average rate of change for the number of African American women who held office at any given time between 1970 & 1993 is   94.43.

Step-by-step explanation:

Here, according to the question:

Number of African American women in elected public office in the United States in the year 1970 = 160

Number of African American women in elected public office in the United States in the year 1993 = 2332

Now, the change in the number of elected women between 1970 & 1993

= Women elected in the year 1993 - Women elected in the year 1970

=  2332 -  160  = 2,172

or, the change in the number of elected women candidates between 1970 & 1993 is 2,172

Now, the difference in the time period is 1993 - 1970 =  23 years

So, \textrm{The average rate of change}  = \frac{\textrm{Total change in the quantity}}{\textrm{Time Interval}} \\=\frac{2172}{23}  = 94.43

Hence, the average rate of change for the number of African American women who held office at any given time between 1970 & 1993 is 94.43.

6 0
4 years ago
A survey of 27 randomly sampled judges employed by the state of Florida found that they earned an average wage (including benefi
Afina-wow [57]

Answer:

a) sample mean x^{bar} = 63

b) 95% confidence interval for the population mean wage (including benefits) for these employees is ( 60.58, 65.42 )

c) sample size is 26

Step-by-step explanation:

given the data in the question

a)  estimate of the population mean

sample mean x^{bar} = ($63.00 per hour) = 63

b)

given that; standard deviation σ = 6.11, sample size n = 27

df = n-1 = 27 - 1 = 26

now at 95% CI, t will be;

∝ = 1 - 95% = 0.05, t_{∝/2} = 0.05/2 = 0.025

t_{∝/2, df} = t_{0.025, 26} = 2.056

Margin of Error E = t_{∝/2, df} × (σ/√n)

Margin of Error E = 2.056 × (6.11/√27)

Margin of Error E = 2.056 × 1.17587

Margin of Error E = 2.4175 ≈ 2.42

CI estimate of the population mean will be; ( 95% )

x^{bar} - E < μ < x^{bar} + E

we substitute

63 - 2.42 < μ < 63 + 2.42

60.58 < μ < 65.42

Therefore, 95% confidence interval for the population mean wage (including benefits) for these employees is ( 60.58, 65.42 )

c)

At 90% confidence level and Margin of Error of 2

sample size n = ?

∝ = 1-90% = 0.10, ∝/2 = 0.10/2 = 0.05

Z_{∝/2} = Z_{0.05} = 1.645

Sample size n = (Z_{∝/2} × σ/ / E )²

we substitute

Sample size n = (1.645×6.11 / 2)²

n = (10.05095 / 2)²

n = ( 5.025475)²

n = 25.255

number of employed judges cant be decimal,

Therefore, sample size is 26

8 0
3 years ago
Lenny drank 1 1/5 cups of water before he exercised. He drank 2 2/3 cups of water after he exercised. How much water did he drin
Sonbull [250]

Answer:

3 and 13/15 cups

Step-by-step explanation:

because I did the math

6 0
3 years ago
Can someone please give me the answer to this problem and explain how to do it?
Romashka-Z-Leto [24]
-5+6a+(-8)+(-3a)=
=-5+6a-8-3a=
=3a+(-13)
5 0
3 years ago
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