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Nata [24]
3 years ago
6

How did the graph of f(x) = x^2 and g(x) = 3/4 x^2 relate?

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0

g(x) = \frac{3}{4} f(x) or g(x) is 3/4 times of f(x) , F(x) and g(x) have common solution or intersecting point in the graph parabola at x=0 i.e. in origin and x = \frac {4}{3}.

<u>Step-by-step explanation:</u>

We have a function f(x) = x^{2} and another function , g(x) = \frac{3}{4} x^{2}. In the graph of y = x^{2} , the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point.

Graphing y = (x - h)2 + k , where h = 0 & k = 0

Function g(x) can be formed with compression in function f(x) by a factor of 3/4 , i.e. g(x) = \frac{3}{4} f(x) or g(x) is 3/4 times of f(x).Domain and range of f(x) and g(x) are same ! Although structure of both functions is same the only difference is g(x) is compressed vertically by a factor 3/4. Both are graph of a parabola with vertex at (0,0). Also, F(x) and g(x) have common solution or intersecting point at x=0 i.e. in origin.

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63

Step-by-step explanation:

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2 years ago
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A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0
3 years ago
The nth term of a sequence is 60-8n. Find the largest number in this sequence.
natka813 [3]

Answer:

52

Step-by-step explanation:

1st term is =60-8=52

a2=60-16=44

a3=60-24=36

a4=60-32=28

a5=60-40=20

a6=60-48=12

....

sI the terms are 52,44,36,28, 20,12,4,-4,-12....

so the largest term is 52

6 0
2 years ago
If you input 2 and 2 is the output and if you input 4 and the output is 6 and if you input 5 and the output is 8 what is the inp
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Answer:

11

Step-by-step explanation:

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3 years ago
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
dem82 [27]
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have? 

Answer: the third option (12 zeros..). 

Use ^ to denote an exponent.. 

f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23.. 


We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial.. 

The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..).. 

The degree is 12, thus it means there are 12 zero's.. 


Answer: the third option (12 zero's )...
3 0
3 years ago
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