Answer:
2.8
Step-by-step explanation:
ur welcome i hope this helps
Answer:
D : {x ∈ R : x≠1}
Step-by-step explanation:
The domain is what values of x can we put into the function and it still works
We cannot have the denominator equal zero
x-1 ≠0
Add 1 to each side
x-1+1 ≠0+1
x≠1
The domain is all real values of x except x=1
D : {x ∈ R : x≠1}
1 -since everything includes 4a, we can factor that to get 4a(a-4b^3+2b^2c)
2 - since 5 and 3 add to 8 and multiply to 15, we can do (n+5)(n+3)
3 - since -5 and -4 add to -9 and multiply to 20, we can do (g-5)(g-4)
4 - since -10 and 3 add to -7 and multiply to 30, we can do (z-10)(z+3)
5 - we can factor out 4y to get 4y(y^2-9).
I got the numbers in 2, 3, and 4 with a guesstimating and checking approach
Answer:
-16/29
Step-by-step explanation:
