At the end of three days,
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
Therefore , At the end of three days,
% of the original amount of liquid remains in Kyle's container .
Answer: 5y^3-7x^5
Step-by-step explanation:
Answer:
0 and 1
Step-by-step explanation:
If a polynomial P(x) is divided by (x + h), then by the Remainder theorem
The remainder is the value of P(- h)
(1)
For P(x) divided by (x - 1) , then the remainder is P(1) = 0
(2)
For P(x) divided by (x + 2) then the remainder is P(- 2) = 1
Answer:
Cómo se vería si estuviera graficado:
2x−y=−2
3x−3y=15
Cómo se vería si lo resolviera graficando:
(−7,−12)