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3 years ago

PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.

Mathematics

1 answer:

Elodia [21]3 years ago

5 0

Answer:

Step-by-step explanation:

2ab*cos(C)=a^2+b^2-c^2

2ab*cos(C)=5^2+4^2-2^2=25+12=37

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Solution :

Assuming $\sigma_1^2=\sigma_2^2$

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Step-by-step explanation:

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