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3 years ago

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Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

Reflect the location of computer B over the line w. Mark this new point as point C. Draw a line from computer A's location to point C. This line will cross line w at the answer point. Things won't be one hundred percent exact since you aren't given any numbers, but this is the basic idea of what to do geometrically.

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To make a disinfecting solution, Alana mixes 2 cups of bleach with 5 cups of

lubasha [3.4K]

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Step-by-step explanation:

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3 years ago

Solve problem below please

NARA [144]

Answer:-30

Step-by-step explanation:kinda hard to tell a little shaky so sorry if it is wrong.

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2 years ago

Read 2 more answers

Which of the following relations is not a function?

goblinko [34]

Answer:

the last one

Step-by-step explanation:

because you have two (-1) and that means it is not a function.

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2 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

I need help with the second one

labwork [276]

the answer you're choosing is correct

8 0

3 years ago