A=p (1+I/k)^kn
A future value 160000
p present value ?
I interest rate 6/100=0.06
K compounded semiannual 2
T time 18-7=11years
160000=p (1+0.06/2)^(2×11)
Divide each side by (1+0.06/2)^(2×11)
P=160,000÷(1+0.06÷2)^(2×11)
P=83,502.8
Hope it helps:-)
Label the points A,B,C
- A = (1,2)
- B = (4,5)
- C = (8,9)
Let's find the distance from A to B, aka find the length of segment AB.
We use the distance formula.

Segment AB is exactly
units long.
Now let's find the distance from B to C

Segment BC is exactly
units long.
Adding these segments gives

----------------------
Now if A,B,C are collinear then AB+BC should get the length of AC.
AB+BC = AC
Let's calculate the distance from A to C

AC is exactly
units long.
Therefore, we've shown that AB+BC = AC is a true equation.
This proves that A,B,C are collinear.
For more information, check out the segment addition postulate.
Answer:
a- (3,4)
b- (0,-4)
c- (-6,2)
d- (0,5)
e- (-4,-5)
Step-by-step explanation:
hope this helps
A: {-4, -2 -1, 2}<br>
B: {-4, 4}<br>
C: {-3, -2, 0, 2}<br>
D: {-4, -2, -1, 0, -2}
Temka [501]
Answer:this is soooo compli
Step-by-step explanation: