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Talja [164]
3 years ago
11

Which expression has the same value as 4x – 3y?

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

4x+(-3y)

Step-by-step explanation:

\\ \rm\longmapsto 4x+(-3y)

  • (-)(-)=(+)
  • (+)(-)=(-)
  • (-)(+)=(-)
  • (+)(+)=(+)

\\ \rm\longmapsto 4x-3y

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Parents wish to have $160,000 available for a​ child's education. If the child is now
Neporo4naja [7]
A=p (1+I/k)^kn

A future value 160000
p present value ?
I interest rate 6/100=0.06
K compounded semiannual 2
T time 18-7=11years

160000=p (1+0.06/2)^(2×11)
Divide each side by (1+0.06/2)^(2×11)
P=160,000÷(1+0.06÷2)^(2×11)
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Hope it helps:-)
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3 years ago
How many posters and picture frames does the store sell on that day?
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What is the question
3 0
3 years ago
5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9) ​
Irina-Kira [14]

Label the points A,B,C

  • A = (1,2)
  • B = (4,5)
  • C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\

Segment AB is exactly 3\sqrt{2} units long.

Now let's find the distance from B to C

B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\

Segment BC is exactly 4\sqrt{2} units long.

Adding these segments gives

AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\

AC is exactly 7\sqrt{2} units long.

Therefore, we've shown that AB+BC = AC is a true equation.

This proves that A,B,C are collinear.

For more information, check out the segment addition postulate.

7 0
3 years ago
can yall help me pls? thanks just pls tell me the right coordinates on this graph pls if u will :) <3
skelet666 [1.2K]

Answer:

a- (3,4)

b- (0,-4)

c- (-6,2)

d- (0,5)

e- (-4,-5)

Step-by-step explanation:

hope this helps

4 0
3 years ago
A: {-4, -2 -1, 2}<br> B: {-4, 4}<br> C: {-3, -2, 0, 2}<br> D: {-4, -2, -1, 0, -2}
Temka [501]

Answer:this is soooo compli

Step-by-step explanation:

5 0
3 years ago
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