The total surface area of the remaining solid is 48(4+✓3) centimeters square.
<h3>How to calculate the surface area?</h3>
Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.
The formula for the total surface area will be:
= Total surface area=2(area of the base)+ parameter of base × height
where,
Height= 8cm
Parameter of base=12(2) = 24
Area of the base= 6×✓3/4×4² = 64✓3/4
The surface area of the remaining solid will be:
= 2(64✓3/4) + 24 × 8
= 2(64✓3/4 + 192
With the hole is a rhombus prism with the following parameters:
diagonal 1 = 6, diagonal 2 = 8, height = 12
The volume is:
V1 =0.5 × d1 × d2 × h
V1 = 0.5 × 6 × 8 × 12
V1 = 96
The dimensions of the hexagonal prism are:
Base edge (a) = 8
Height (h) = 12
The volume is
V2 = (3✓(3)/2)a²h
V2 = (3✓3)/2) × 8² × 12
V2 = 1152✓3
The remaining volume is
V = V2 -V1
V = 1152✓3 - 96
Learn more about the hexagonal prism on:
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Answer:
The first one is 360 degrees. The second one is 1080.
Step-by-step explanation:
The sum of the interior angles of a quadrilateral are always 360. If you subtract 90 from 360 to get 270. Multiply 270 by 4 to get 1080.
Answer:
I cannot see the picture
Step-by-step explanation:
Answer:
3 and 1
Step-by-step explanation:
Similarly each term is 1/3 of the previous term. This is a geometric sequence.
9/3 = 3
3/3 =1
-2=-x+x square-4
firstly regroup the equation
x square-2x+x-2=0
x square-x-2=0
multiply the first term by the last term.(I.e x square multiply by -2=-2x square)
product of factor = -2x 1
sum of factor= -2x+1(x)= -1
x square -2x+x-2=0
open the bracket:
x(x-2)+1(x-2)=0
x=1 or x=-2
Therefore; x=-1 or x=2
