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Gelneren [198K]
3 years ago
6

UESTION 2 120 MARKS Underground cable breakdown often occur due to the unpredictable deterioration rate of the cable insulation.

Cable replacement can be very costly without regular mainte A 9-month study on an underground cable insulation had been conducted to check for the length of the cable insulation that have been deteriorated using fluorescence microscope in order to estimate the maintenance cycle. Table 1 shows the data measured every 3 months during the study Table 1 Time, t (month) Deteriorated cable insulation length, I 1.35 3.72 7.28 15.45 (a) Generate a third order polynomial using Newton's interpolation method to describe the variable of the deteriorated cable insulation length, (t) with respect to time (in month). Write the polynomial in the form of At3BtCt D, where [10 marks] A, B, C and D are constants. (b) According to regulation, the cable insulation requires replacement if it is degraded by 6 mm. Calculate the replacement time using Newton Raphson method with initial guess of 6 months from the polynomial generated in part (a). Perform THREE iterations only and calculate true percent relative error for the final iteration answer [10 marks if the true value of the replacement time is 5 months.
Mathematics
1 answer:
ANEK [815]3 years ago
4 0
Listen to tame impala that’s that’s the answerb
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fredd [130]
Hi there I know the answer but it was confusing so it has to be D or B
6 0
3 years ago
AB is the angle bisector of ∠CAD. Solve for x.
Sliva [168]

Answer: x=7

Step-by-step explanation:

Since AB is a bisector, it cuts the angle in half, and since we know that the angle is a right angle, we know it’s 90 degrees, so knowing that you use the equation 7x-4= 45 (since 45 is half of 90), add 4 to both sides so you have 7x=49, the divide 49 by 7 and you get 7, so x= 7

3 0
3 years ago
Hank invested a total of $20,000, part at 7% and part at 10%. How much did he invest at each rate if the total interest earned i
jolli1 [7]

Answer:

The amount invested at 7% is $12,000 while the amount invested at 10% is $8,000

Step-by-step explanation:

The given parameters are;

The total amount Hank invested = $20,000

The interest earned in one year = $1640

Hank invested part of the $20,000 at 7% interest and part of the $20,000 at 10%

Let the part invested at 7% = X and the part invested at 10% = Y, we have;

7% of X + 10% of Y = $1640 which gives;

0.07×X + 0.1×Y = $1640.....................(1)

X + Y = $20,000.................................(2)

Multiply equation (1) by 10 and subtract equation (1) from equation (2) to get;

X + Y - 10×(0.07×X + 0.1×Y) = $20,000 - 10×$1640

X - 0.7·X - Y - Y = $20,000 - $16,400 = $3,600

0.3·X = $3,600

X = $3,600/0.3 = $12,000

X = $12,000

Y = $20,000 - X = $20,000 - $12,000 = $8,000

Y = $8,000

Therefore, the amount invested at 7% = $12,000 and the amount invested at 10% = $8,000.

7 0
3 years ago
Read 2 more answers
Does (3,5) and (-3,-5) lie in the same quadrant
Arlecino [84]

Answer:

no they don't one lies in  quadrant 1 while the other is in quadrant 3

Step-by-step explanation:

4 0
3 years ago
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What is 2491 divided by 53
Darina [25.2K]

Answer:

47

Step-by-step explanation:

6 0
3 years ago
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