Assume f(x) = 2x – 3 and g(x) = 5

ivanzaharov [21]

I believe the answer is 0.24

4 0

3 years ago

In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is

Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

$\mu=np=300\times0.077=23.1$

$\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62$

Now, using formula $z=\dfrac{x-\mu}{\sigma}$ , the z-value corresponding to 26 will be :-

$z=\dfrac{26-23.1}{4.62}\approx0.63$

Using standard distribution table for z , we have

P-value= $P(z\geq0.63)=1-P(z$

$=1-0.7356527=0.2643473\approx0.2643$

Hence, the probability that at least 26 in the sample are unemployed =0.2643

6 0

3 years ago

G Blue Ribbon taxis offers shuttle service to the nearest airport. You look up the online reviews for Blue Ribbon taxis and find

Dominik [7]

Answer:

This is a biased sampling method for obtaining customer opinions because those who take the time to write an online review are likely to do so because they are upset with the service they received.
The direction of the bias is likely to overestimate the proportion of customers who have a negative opinion on the service.

Step-by-step explanation:

1) There are groups which are not represented in the survey like those who don't use web. And also those who take the time to write an online review are likely to do so because they are upset with the service they received.

2) Those who had negative experience are more likely to write a review than those who had not.

4 0

3 years ago

For dessert you get to choose between 3 types of pie, 2 types of ice cream, and 3 drinks. How many pie, ice cream, and drink com

sladkih [1.3K]

You simply multiply all the options
3x2x3= 18 possibilities

4 0

4 years ago

Read 2 more answers

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

Assume f(x) = 2x – 3 and g(x) = 5 - 2x. Find