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Andrej [43]
3 years ago
10

A passenger rode the subway 2 blocks west and then 10 south. If all the blocks are the same length what is the value of the slop

e of the line from where the passenger began to where he finished

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

The slope of the line is 5

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

I have created an illustration which is attached below in order to help you understand the situation. As we are told the passenger rode the subway from point (0 , 0) to point (-2, 0). Then he rode the subway from point (-2, 0) to the final destination of point (-2 , -10). In order to find the value of the slope we need to use the slope formula which is

Slope = \frac{y_{2}-y_{1} }{x_{2}- x_{1} }

Now we just plug in the values of the starting point and final destination in order to find the slope of the line.

Slope = \frac{(-10) - (0)}{(-2)-(0)}

Slope = \frac{-10}{-2}

Slope =5

Finally we can see that the slope of the line is 5

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Answer:

x= 12 and y= 2

Step-by-step explanation:

First you would line up the equations so the x's and y's are on top of each other. Then you would multiply x+y=14 by 3 to give you 3x+3y=42. After that you subtract 2x-3y=30 and 3x+3y=42 to give you an answer of x=12. After that, you plug in x with 12 in the equation x+y=14. You subtract 12 from both sides to get an answer of 2. So ur solution is (12,2)

   

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Mr. Wilson wants to park his car in his parking garage. To find the cost, he uses the equation D= 3H+6, where D represents the t
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Answer: 8\ hours

Step-by-step explanation:

You know that Mr. Wilson uses the following equation to find the cost:

D= 3H+6

Then, if Mr. Wilson spent $30, you can follow these steps in order to calculate how many hours he parked in the parking garage:

1. You need to substitute D=30 into the given equation:

30= 3H+6

2. Now, you must solve for "H":

30= 3H+6\\\\30-6=3H\\\\24=3H\\\\\frac{24}{3}=H\\\\H=8

Therefore, based on the result, you can conclude that Mr. Wilson parked his car in the parking garage for 8 hours.

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Please hepl with math
Ivenika [448]

Answer:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

Step-by-step explanation:

We are given the expression to be simplified:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

a^{p+q} = a^p \times a^q

Let us use it to solve the powers of 5 in the given expression.

\therefore we can write:

5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}

5^{n+1} = 5^n\times 5

The given expression becomes:

\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}

Taking common 5^{n+1} from the numerator and

Taking common 5^{n} from the denominator

\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}

\therefore The answer is:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

6 0
3 years ago
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