Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
Answer:
x=-2
Step-by-step explanation:
4+8x=-12
-4 -4
8x = -16
/8 /8
x = -2
The answer to this question is 22
Answer:
Step-by-step explanation:
We have to diagonalize the matrix
![\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%260%5C%5C5%261%264%5C%5C0%261%261%5Cend%7Barray%7D%5Cright%5D)
we have to solve the expression
Thus, by applying the determinant we obtain the polynomial
and the eigenvector will be
HOPE THIS HELPS!!
Answer:
The answer is "3.329".
Step-by-step explanation:
Please find the complete question in the attached file.
