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3 years ago

What is the area of the right triangle with sides 10,26 and 24

Mathematics

2 answers:

lapo4ka [179]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf 120 \ units^2}}$

Step-by-step explanation:

We are asked to find the area of a triangle. The formula for calculating this is:

$a= \frac{1}{2} bh$

This is a right triangle, so the base and height are the legs of the triangle. The 2 smallest sides are the legs because the longest side is the hypotenuse. Since the side lengths are 10, 26, and 24, the base and height must be 10 units and 24 units.

b= 10 units
h= 24 units

Substitute these values into the formula.

$a= \frac{ 1}{2} ( 10 \ units)(24 \ units)$

Multiply the numbers in parentheses.

$a= \frac{1}{2}(240 \ units^2)$

Multiply by 1/2 or divide by 2.

$a= 120 \ units^2$

The area of the triangle is <u>120 units squared.</u>

solniwko [45]3 years ago

3 0

Answer:

Area = 120

Step-by-step explanation:

Area = 1/2 bh

Area = 1/2 (10)(24)

Area = 1/2 (240)

Area = 120

The area of the right triangle is 120

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Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares

FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

$f(x)=\frac{24}{1+e^{-1.3x}}$

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at $y=\frac{24}{2}$ i.e between 0 to 12

So, we can take $y=\frac{24}{2}$ and then solve for x.

$\frac{24}{2}=\frac{24}{1+e^{-1.3x}}$

⇒ $2=1+3\exp{-1.3x}$

⇒ $1=3.\exp{-1.3x}$ ⇒ $\frac{1}{3}=\exp{-1.3x}$

⇒ log 3=-1.3x

⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82

5 0

4 years ago

Identify the missing numbers below:

IRISSAK [1]

Answer:

A = 7.7

b = 26

Step-by-step explanation:

$(3.5 \times 10^{16})(2.2 \times 10^{10}) = A \times 10^b \\ 3.5 \times 2.2 \times 10^{16} \times 10^{10}= A \times 10^b \\ 7.7 \times {10}^{16 + 10} = A \times 10^b \\ 7.7 \times {10}^{26} = A \times 10^b \\ equating \: like \: terms \: on \: both \: sides \\ A = 7.7 \\ 10^b = {10}^{26} \\ \implies \: b = 26$