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3 years ago

Hi! Can someone help me with this? Properties and Logarithmic Functions.

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

$2\log_{10}x + \log_{10}5 = \log_{10}x^2 + \log_{10}5 = \log_{10}5x^2$

So the answer is $\log_{10}5x^2$

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I used the log rules

y*log(x) = log(x^y)

log(x) + log(y) = log(x*y)

these rules apply to any log base (not just base 10).

You might be interested in

Solve the above question.

Serga [27]

Answer:

gcd(20a,14b)

Step-by-step explanation:

add 7a and 3a, and add 5b to 2b,

you're left with 10a + 7b, times two to both, and you have

20a + 14b

so the answer is gcd(20a,14b)

i have no clue i haven't done this before so thats what i'm guessing happens? good luck :,)

8 0

3 years ago

Someone plz help to become brainliest and get points !! :) plz answer truthfully

lutik1710 [3]

Answer: OPTION A.

Step-by-step explanation:

The volume of a cylinder can be found using the following formula:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height of the cylinder.

Analizing the data given in the exercise, you can identify that:

$h=5\ in$

Since the radius is half the diameter, this is:

$r=\frac{d}{2}\\\\r=\frac{3\ in}{2}\\\\r=1.5\ in$

Knowing these values, you can substitute them into the equation and then evaluate, in order to calculate the volume of the can. This is:

$V=\pi (1.5\ in)^2(5\ in)\\\\V=11.25\pi\ in^3$

4 0

4 years ago

Work out 40 % of 8.1

Aloiza [94]

Answer

<h2>3.24 this is the answer </h2>

6 0

3 years ago

Read 2 more answers

7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many

BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

$_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\$

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

$_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\$

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

$_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\$

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>

5 0

3 years ago

How to i figure this out ?

fiasKO [112]

Tip - for finding the surface area of a triangle put two of them together so it forms a square find the area of that square and divide it by 2

5 0

4 years ago