Question

Work out the given expression (6x²y³-3xy⁴)÷3xy²​

Answer 1

Answer:

$\boxed{=y(2x-y)}$

Step-by-step explanation:

$\dfrac{6x^2y^3-3xy^4}{3xy^2} \\\\=\dfrac{3xy^3(2x-y)}{3xy^2} \\\\=y(2x-y)\\\\=2xy-y^2$

Answer 2

Answer:

$\frac{3x {y}^{2} (2xy - {y}^{2} )}{3x {y}^{2} } \\ 2xy - {y}^{2}$