All categories

3 years ago

Rates/Proportional Relationships.

Mathematics

1 answer:

brilliants [131]3 years ago

3 0

Answer:

KKRNF.EWBVERUVHUYLERBVHJDBREVVVLEKVOEUFJOE

Step-by-step explanation:NWEKFK.EWBFEWHBV.KWEUF67OFVD.KFERLUGVK34UGILBEFLIUBYETRNTYM6

You might be interested in

The price of a sweater is $5 less than twice the price of a shirt. if four sweaters and three shirts cost $200, find the price o

Mandarinka [93]

Sw+5=2sh
4sw+3sh=200 
4(2sh-5)+3sh=200

$20, $35 The shirts are $20 and the sweaters are $35

8 0

3 years ago

What is the scale factor from ABC to DEF? (20 points)

NeX [460]

Answer:

C.1/6

Step-by-step explanation:

yan po ung tamang sagut thank you

7 0

2 years ago

What is .4, 5/8, 38%, .5 from least to greatest

MrRa [10]

Least to Greatest: 38%, .4, .5, 5/8

5 0

3 years ago

Read 2 more answers

The sum of the digits of a two digit number is 7. If 9 is subtracted from the number, the answer will be the number with the dig

cupoosta [38]

Just work through step by step
Follow each point until you reach one answer
Digits = 7
-9 = reverse

16 - 9 = 7        x
25 - 9 = 16      x
34 - 9 = 25      x
43 - 9 = 34      Y
52 - 9 = 43      x
61 - 9 = 52      x

4 + 3 = 7
43 - 9 = 34 - the digits have been reversed

43

5 0

3 years ago

Read 2 more answers

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

3 years ago