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sergiy2304 [10]
3 years ago
12

Geometry, please answer question ASAP

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

Yes, PQR ~ TSV with a scale of 1 : \sqrt{3}

Step-by-step explanation:

Yes the triangles are congruent for the statement given in option C

The scale 1 : \sqrt{3} shows that the side lengths are proportional

PQ/TS = QR/SV

3\sqrt{3}/6/\sqrt{3} and that's simplified as 1/\sqrt{3}

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Dovator [93]

some problem , pls refer the attachment for your answer

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>~</em>

5 0
3 years ago
Please help! :)
Olin [163]

Answer:

long term goal is to take on bigger, more challenging targets so I can assess my abilities. I plan on shaping myself during this initial time so that I'm prepared to deliver on bigger targets later. Although I've been in this field for a while now, I haven't been able to utilize my entire set of skills.

Step-by-step explanation:

hope it helps a little idk how to answer that completely

3 0
3 years ago
Use f(x) = 1)2 and f^-1(x) = 2x to solve the problems. a) f(2) b)f^-1(1) c)f^-1(f(2))​
Luden [163]

a) f (2)  = 1

b) f^{-1}(1)=2

c) f^{-1}(f(2))=2

<u>Step-by-step explanation:</u>

f^{-1} - Indicates that we have to find the inverse of the function

Given data:

f(x)=\left(\frac{1}{2}\right) x --------> eq.1

f^{-1}(x)=2 x ---------> eq.2

To find f(2), f^{-1}(1), f^{-1}(f(2))

Case a)

Now, substitute x = 2 in the equation 1 to find f (2)

 f(2)=\left(\frac{1}{2}\right) \times 2=1

Case b)

Now, substitute x = 1 in the equation 2 to find  f^{-1}(1)

  f^{-1}(1)=2(1)=2

Case c)

In general,

    f^{-1}(f(x))=f\left(f^{-1}(x)\right)=x

Thereby,

   f^{-1}(f(2))=2 \text { where } x=2

5 0
3 years ago
Y = 3x – 21 is it proportional
pochemuha

Answer:

yes  

Step-by-step explanation:

4 0
3 years ago
Round 25,386 to the nearest 1,000
Nonamiya [84]
25,000 because anything below 500 is rounded down 
7 0
4 years ago
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