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stepladder [879]
3 years ago
6

Lines RS, TV in SW are shown which statements are true about these lines check all that apply

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0

Answer:

Line SW has a undefined slope

Line TV has a slope of 0

Lines RS and TV are parallel

Step-by-step explanation:

Verify each statement

Part 1) Line RS has a slope of 6

The statement is false

Because, line RS is a horizontal line (is parallel  to the x-axis)

so

The slope of line RS is equal to zero

<em>Verify</em>

we have

R(-8,6) and S(2,6)

Applying the formula of slope

m=(6-6)/(2+8)

m=0/10=0

Part 2) Line SW has a undefined slope

The statement is true

Because, line SW is a vertical line (is parallel to the y-axis)

The slope of a vertical line is undefined

<em>Verify</em>

we have

S(2,6) and W(2,-8)

Applying the formula of slope

m=(-8-6)/(2-2)

m=-14/0 -----> is undefined

Part 3) Line TV has a slope of 0

The statement is true

Because, line TV is a horizontal line (is parallel  to the x-axis)

so

The slope of line TV is equal to zero

<em>Verify</em>

we have

T(-6,-4) and V(8,-4)

Applying the formula of slope

m=(-4+4)/(8+6)

m=0/14=0

Part 4) Lines RS and TV are parallel

The statement is true

Because, line RS and line TV are horizontal lines (are parallel  to the x-axis)

Remember that if two lines are parallel, then their slopes are the same.

Both slopes are equal to zero

Part 5) Line SW is perpendicular to line RS but no to line TV

The statement is false

Because, Line SW is perpendicular to line RS and line TV

(A horizontal line is perpendicular to a vertical line. so it would have to be perpendicular to both RS and TV)

dlinn [17]3 years ago
5 0

Answer:

the middle three

Step-by-step explanation:

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Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer:  {x = 1 , y=1, z=0

6 0
3 years ago
On the first day of ticket sales the school sold 1 senior citizen ticket and 5 child tickets for a total of $60. The school took
Stells [14]

Answer:

Step-by-step explanation:

Let's start off with the first equation

5x + y = 60

We need to find what X and Y are.

Let's try subtracting a few numbers from 60.

Let's do 60 - 55 = 5

11x5 = 55

11 = Children Ticket Cost

5 = Seniors Ticket Cost

Without them being the same price!

So using the numbers we found, we can now solve the second one

14x5 = 70

11x11 = 121

70 + 121 = 191

There we go!

Hope this helped! Please give brainiest if you can :)

3 0
3 years ago
Read 2 more answers
The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term
rjkz [21]

Answer:

3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

   = 3(x² - 4x + 4) + 4

    = 3x² - 12x + 12 + 4

     = 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

5 0
3 years ago
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Hunter-Best [27]
the answer is A : m=-1
5 0
2 years ago
Read 2 more answers
Solve the equation<br> (x-3)^3-( x - 1 )^3 + 7x^2 = 7(3x - 4 )
Yakvenalex [24]

Answer:

x= -1 or x = -2

Step-by-step explanation:

Your equation:

(x−3)^3−(x−1)^3+7x^2=7(3x−4)

Step 1: Simplify both sides of the equation.

x^2+24x−26=21x−28

Step 2: Subtract 21x-28 from both sides.

x^2+24x−26−(21x−28)=21x−28−(21x−28)

x^2+3x+2=0

Step 3: Factor left side of equation.

(x+1)(x+2)=0

Step 4: Set factors equal to zero.

x+1=0 or x+2=0

which equals to x=−1 or x=−2

8 0
2 years ago
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