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Galina-37 [17]
3 years ago
8

Tell whether each order pair is a solution of the equation.

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

1.) (2,1) is a solution

2.) (4,3) is NOT a solution

Step-by-step explanation:

1.) (2,1)

These are these mean (x,y)

2=x and 1=y

You want to substitute the numbers for the letters in the equation.

so.

2(2)+1=5

4+1=5

5=5, This statement is true so (2,1) is a solution.

2.) Same as above. 4=x and 3=y

4(4)-3(3)=10

16-9=10

7 Does Not Equal 10, Therefore, (4,3) is Not a solution to the equation.

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It costs $3.45 to buy 3/4 lb of chopped walnuts. What is the unit price for one
Anettt [7]

Answer:

Step-by-step explanation:

3.45/(3/4)

3.45/0.75

4.6$ per pound

6 0
3 years ago
If f(x)= 2x^2 -4x and g(x) = 5 – 2x, evaluate f(x) – g(x) for x = 5
Orlov [11]
<span>If f(x)= 2x^2 -4x and g(x) = 5 – 2x, evaluate f(x) – g(x) for x = 5

you first plug in 5 for x in both equations...
(2(5)^2-4(5))=f(x)
5-2(5)=g(x)

now you evaluate...
(2(25)-20)-5-10
50-30-15
20-15=5
Answer:
5


</span>
6 0
3 years ago
9x+5=(x+3)what is the value of x
GenaCL600 [577]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $⁢1800, which was to be divided equally among t
CaHeK987 [17]
Let's say "p" people were going to the expedition initially, and the cost for each was "c", now, we know the total cost is 1800, so for "p",  folks that'd be  1800/p how much each one cost, namely, how many times "p" goes into 1800.

well, prior to leaving, 15 dropped out, so that leaves us with " p - 15 ", and the cost "c" bumped up to " c + 27 " for each.

\bf \begin{cases}&#10;\cfrac{1800}{p}=\boxed{c}\\\\&#10;\cfrac{1800}{p-15}=c+27\\\\&#10;----------\\&#10;\cfrac{1800}{p-15}=\boxed{\cfrac{1800}{p}}+27&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\cfrac{1800}{p-15}={\cfrac{1800}{p}}+27\impliedby &#10;\begin{array}{llll}&#10;\textit{let's multiply both sides by}\quad  p(p-15)\\&#10;\textit{to get rid of the denominators}&#10;\end{array}

\bf 1800p=1800(p-15)+27[p(p-15)]&#10;\\\\\\&#10;1800p=1800p-27000+27(p^2-15p)&#10;\\\\\\&#10;0=-27000+27(p^2-15p)\implies 0=-27000+27p^2-405p&#10;\\\\\\&#10;\textit{now, let's take a common factor of }27&#10;\\\\\\&#10;0=p^2-15p-1000\implies 0=(p-40)(p+25)\implies p=&#10;\begin{cases}&#10;\boxed{40}\\&#10;-25&#10;\end{cases}

well, you can't have a negative value of people... so it has to be 40.

so, 40 folks were initially going, then 15 dropped out, how many went on the expedition?  40 - 15.
3 0
4 years ago
What’s the correct answer for this?
snow_tiger [21]

Answer

D.

Explanation

mIH = 44

mIJ = 46

mJK = 77

ADDING THEM ALL TO FIND THE MEASURE OF m<HOK

<HOK = 44+46+77

<HOK = 167°

5 0
3 years ago
Read 2 more answers
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