You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.
Answer:
25 degrees
Step-by-step explanation:

No they should multiplied before adding
We know that
the equation of the line in standard form is
Ax+By=C
the equation of the line <span> in the slope-intercept form is
</span><span>y +1 = 2/3 (x - 8)-----> y+1=(2/3)x-(16/3)----> y-(2/3)x=(-16/3)-1
</span>y-(2/3)x=(-19/3)----> multiply by 3-----> -2x+3y=-19
the answer is
-2x+3y=-19
<span>I verify that the points belong to the given line
for the point (8,-1)
-2*8+3*(-1)=-19--------> -16-3=-19-----> -19=-19------> is ok
for the point (2,-5)
-2*2+3*(-5)=-19------> -4-15=-19------> -19=-19-----> is ok</span>